Answer:
1 mole of ferric contains 2 moles of iron,and 12 moles of oxygen atoms, and three moles of sulphate ions
The mole fraction of KCl in the solution is 0.1051
calculation
mole fraction of KCl in solution = moles of KCl / total number of moles(moles of KCl +moles of H2O)
moles=mass/molar mass
mass of KCl=32.7g
molar mass of KCl= 39 +35.5
moles of KCl is therefore= 32.7g/74.5 g/mol=0.439 moles
find the moles of H2O= mass of H2O/molar mass
mass of H2O=100-32.7=67.3g
molar mass of H2O=( 1 x2) +16=18 g/mol
moles = 67.3/18 =3.739 moles
total moles=3.739+0.439=4.178 moles
mole fraction is therefore=0.439/4.178=0.1051
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Q = mct
-Q= energy in Joules
-m = mass in grams
-c= specific heat capacity in J/g degree C
-t = delta temperature in degrees Celsius
So,
Q = m c t
Q = (7 grams)(0.448J/g C)(750 C - 25 C)
Q = 2273.6 J
Your final answer = 2273.6 Joules
Answer:
4 moles
Explanation:
= 
= 2 (moles)
CH4 + 2O2 → CO2 + 2H2O
1 : 2 : 1 : 2
2 (moles)
⇒ 
= 2 × 2 ÷ 1 = 4 (moles)
