Question

In the figure to the right, AE + DC = 1 1/5 cm, AB = 1 3/4 cm, DE = 1 1/4 cm, and BC = 1 3/10 cm. Find the perimeter of the figure.
NEED BY 4:30 where I am it’s 4:20!!!!!!!!! ANY USELESS ANSWERS R BANNED! WILL MARK BRAINLIEST IF RIGHT ANSWER!

Answer 1

Answer:

P= 5.5 cm

Step-by-step explanation:

The Perimeter of Plane Shapes

If we are given a plane shape, the perimeter is the measurement of the boundary of it. In case the shape is made of lines, the perimeter is the sum of the lengths of all of them.

We are given an irregular shape, we only need to add all the sides. But we don't have all the individual sides. Let's write the expression for the perimeter.

P=AE+ED+DC+CB+BA

We have: AE + DC = 1 1/5 cm, AB = 1 3/4 cm, DE = 1 1/4 cm, and BC = 1 3/10 cm. Note we don't have AE or DC, but we have their sum, so

P=AE+DC+ED+CB+BA

Recall that AB=BA, the order of the letters is not important. The perimeter is

$\displaystyle P=1\frac{1}{5}+1\frac{1}{4}+1\frac{3}{10}+1\frac{3}{4}$

We add the integer parts separate from the fractions

$\displaystyle P=4+\frac{1}{5}+\frac{1}{4}+\frac{3}{10}+\frac{3}{4}$

Now we use the common denominator (Least Common Multiple or LCM ) which is 20:

$\displaystyle P=4+\frac{4+5+6+15}{20}$

Operating

$\displaystyle P=4+\frac{30}{20}$

Simplifying

$\displaystyle P=4+\frac{3}{2}$

$\displaystyle P=\frac{11}{2}=5.5\ cm$