Write 47% as a fraction is simplest form.
1 answer:
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Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:
P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:
P = 0.59
Answer:
And we can find this probability using the normal standard distribution table and we got:
And the percentage faster than 13.28 seconds would be 91.9%
Step-by-step explanation:
Let X the random variable that represent the runtimes of a population, and for this case we know the distribution for X is given by:
Where and
We want to find this probability:
And we can use the z score formula given by:
Using this formula we have:
And we can find this probability using the normal standard distribution table and we got:
And the percentage faster than 13.28 seconds would be 91.9%