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DochEvi [55]
3 years ago
9

Find the least common multiple or LCM

Mathematics
1 answer:
MAXImum [283]3 years ago
8 0
ANSWER:

Mrs. Cook should buy 2 packages of candy.

This is as:

LCM = 72

2 packages of candy = 36 × 2 = 72 pieces

72 ÷ 24 = 3

Therefore, as 72 divided by 24 results in a whole number without any left over, the answer must be 2 packages.

Hope this helps! :)
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A rectangle has a length of 3x inches. The width of the rectangle is (2x+6) inches more than the length. A) Find the perimeter o
s2008m [1.1K]
Perimeter = 2*(length +width)
perimeter = 2*(3x + (3x +(2x+6)))
.. = 2*(3x +3x +2x +6)
.. = 2*(8x +6)
perimeter = 16x +12

If x=3, the perimeter is 16*3 +12 = 60 inches.
7 0
3 years ago
HELP ME ASAP QUIZ
Gnoma [55]

Answer:

E

Step-by-step explanation:

for b bananas sold 0.40 profit

for a apples

7 0
2 years ago
PLEASE HELP!!
FromTheMoon [43]

Step-by-step explanation:

Given

Model to Actual = 5:9

5cm in Model = 9cm actual

1cm in model = (9/5)cm = 1.8cm

36cm in model = 1.8cm x 36 = 64.8cm

3 0
2 years ago
In one year, the Perseid meteor shower had a meteor appear every 1 1/5 minutes on average. That same year, the Leonid meteor sho
RoseWind [281]

Answer:

325,452 more meteors fell during the Perseid meteor shower

Step-by-step explanation:

An year has 365 days.

Each day has 24 hours.

Each hour has 60 minutes.

Minutes in an year:

365*24*60 = 525600

Persoid:

1 + \frac{1}{5} = 1 + 0.2 = 1.2

One each 1.2 minutes. How many during an year?

1 meteor - 1.2 minutes.

x meteors - 525600 minutes.

1.2x = 525600

x = \frac{525600}{1.2}

x = 438000

438,000 meteors fell during the Persoid shower.

Leonid:

4 + \frac{2}{3} = 4.67

One each 4.67 minutes. How many during an year.

1 meteor - 4.67 minutes.

x meteors - 525600 minutes.

4.67x = 525600

x = \frac{525600}{4.67}

x = 112548

112,548 meteors fell during the Leonid Shower.

How many more meteors fell during the Perseid meteor shower?

438,000 - 112,548 = 325,452

325,452 more meteors fell during the Perseid meteor shower

5 0
2 years ago
What would you pay for a $210,000 debenture bond that matures in 15 years and pays $10,500 a year in interest if you wanted to e
Hoochie [10]
<span>Let's say you wanted to earn a yield of 8%. $210,000 x .31524 = $66, 200.4 +$10,500 x 8.55948 = $89, 874.54 Use the tables to find .31524 (which is 8% @ 15 periods for present value of 1) and 8.55948 (which is 8% @ 15 periods for present value of an ordinary annuity of 1) You would pay a total of $156, 074.94</span>
7 0
3 years ago
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