Question

A sequence of transformations maps ∆ABC to ∆A′B′C′. The sequence of transformations that maps ∆ABC to ∆A′B′C′ is a reflection across the (1.)_____ followed by a translation (2.)_____ .
Answers for (1.) * y-axis
* x-axis
* Line y = x
* Line y = -x


Answers for (2.) * 4 units to the right and 10 units up
* 8 units to the right and 4 units up
* 10 unit to the right and 2 units up
* 10 units to the right and 4 unit s up

i need a answer for 1 and 2

Answer 1

Answer:  The answer is (1) (B) y = x and (2) (D)  10 units to the right and 4 units up.

Step-by-step explanation: We are given that ΔA'B'C' is formed after a sequence of transformations applied to ΔABC.

The first is a reflection across a line and second is a translation.

The co-ordinates of point C are (-4, -2). After reflection from the line y = x, the co-ordinates becomes  (2, -4).

Also, the coordinates of point C' are (12, 0).

So, to reach point C' from point C, we should add 10 units to the x-coordinate and 4 units to the y-coordinate.

That is, the translation of 10 units right and 4 units up.

Thus, the complete transformation is

The sequence of transformations that maps ∆ABC to ∆A′B′C′ is a reflection across the line y = x followed by a translation 10 units right and 4 units up.

Thus, the correct answer is (1) y = x and (2) 10 units to the right and 4 units up.

Answer 2

the right answer and i took this on plato edmentum i put in 1 =y=x and 2 is 10 units to the right and 4 units up