A sequence of transformations maps ∆ABC to ∆A′B′C′. The sequence of transformations that maps ∆ABC to ∆A′B′C′ is a reflection ac
ross the (1.)_____ followed by a translation (2.)_____ .
Answers for (1.) * y-axis
* x-axis
* Line y = x
* Line y = -x
Answers for (2.) * 4 units to the right and 10 units up
* 8 units to the right and 4 units up
* 10 unit to the right and 2 units up
* 10 units to the right and 4 unit s up
i need a answer for 1 and 2
Answers for (1.) * y-axis
* x-axis
* Line y = x
* Line y = -x
Answers for (2.) * 4 units to the right and 10 units up
* 8 units to the right and 4 units up
* 10 unit to the right and 2 units up
* 10 units to the right and 4 unit s up
i need a answer for 1 and 2
2 answers:
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Greetings.
The answer is x = -2.
Explanation:
By solving the Absolute-Value Equation. We give them 2 conditions.
<em>When x ≥ 0 and When x < 0</em>
<em>The different is that When x ≥ 0, |x-a| = x-a as defined.</em>
<em>And when x < 0. |x-a| = -x+a as defined.</em>
( 1 ) - When x ≥ 0 for |x-1| and |x+5|
When x ≥ 0, |x-1| = x-1 and |x+5| = x+5
Therefore, x-1 = x+5
Because the equation is false. Therefore, The condition (1) doesn't apply.
( 2 ) - When x ≥ 0 for |x-1| and x < 0 for |x+5|
This time, we try another condition.
When x ≥ 0, |x-1| = x-1 and When x < 0, |x+5| = -x-5.
And we get the answer, |x-1| = |x+5| when x = -2.
But we haven't tried the last condition.
( 3 ) And that is when x < 0 for both terms.
|x-1| = -x+1 (x < 0)
|x+5| = -x-5 (x < 0)
The equation is not true. Therefore, the answer is x = -2.