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grin007 [14]
3 years ago
15

Select the number in which the digit 6 is ten times the value

Mathematics
1 answer:
Verizon [17]3 years ago
5 0

Answer:

0.164

9.568

Step-by-step explanation:

we have the number

1.836

Decompose the number in digit values

we know that

1.836=1+8(0.10)+3(0.01)+6(0.001)

1.836=1+0.80+0.03+0.006

The value of the digit 6 is 0.006

Ten times the value of the digit 6 is

10(0.006)=0.06

<u><em>Verify each case</em></u>

case 1) we have

0.164

The value of the digit 6 is 0.06

Compare with the value of ten times the value  of the digit 6 in 1.836

0.06=0.06

therefore

The value of the digit 6 in this number is equal to ten times the value

of the digit 6 in 1.836

case 2) we have

9.568

The value of the digit 6 is 0.06

Compare with the value of ten times the value  of the digit 6 in 1.836

0.06=0.06

therefore

The value of the digit 6 in this number is equal to ten times the value

of the digit 6 in 1.836

case 3) we have

3.658

The value of the digit 6 is 0.6

Compare with the value of ten times the value  of the digit 6 in 1.836

0.6 \neq 0.06

therefore

The value of the digit 6 in this number is not equal to ten times the value

of the digit 6 in 1.836

case 4) we have

186.9

The value of the digit 6 is 6

Compare with the value of ten times the value  of the digit 6 in 1.836

6 \neq 0.06

therefore

The value of the digit 6 in this number is not equal to ten times the value

of the digit 6 in 1.836

case 5) we have

56.82

The value of the digit 6 is 6

Compare with the value of ten times the value  of the digit 6 in 1.836

6 \neq 0.06

therefore

The value of the digit 6 in this number is not equal to ten times the value

of the digit 6 in 1.836

case 6) we have

1.836

The value of the digit 6 is 0.006

Compare with the value of ten times the value  of the digit 6 in 1.836

0.006 \neq 0.06

therefore

The value of the digit 6 in this number is not equal to ten times the value

of the digit 6 in 1.836

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Answer:

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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The standards for glass thickness call for the glass to average 0.325 inch with a standard deviation equal to 0.065 inch.

This means \mu = 0.325, \sigma = 0.065

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This means that n = 44, s = \frac{0.065}{\sqrt{44}}

What is the probability of x >= 0.337 if the windows meet the standards?

This is 1 subtracted by the p-value of Z when X = 0.337. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.337 - 0.325}{\frac{0.065}{\sqrt{44}}}

Z = 1.225

Z = 1.225 has a p-value of 0.8898

1 - 0.8898 = 0.1102

0.1102 = 11.02% probability of x >= 0.337 if the windows meet the standards.

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