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Karolina [17]
3 years ago
7

PLEASE HELP

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
5 0

Answer:

y = 2

Step-by-step explanation:

I will solve this problem, using the elimination method.

-2(5x - 3y) = -11

-10x + 6y = 22

2x - 6y = -14

Subtract and divide for x

-8x = 8

x = -1

Input -1 into the equations

2(-1) - 6y = -14

-6y - 2 = -14

-6y = -12

y = 2

Thanks!

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Please help me out please
Fantom [35]

Answer:

the area of the hexagon is approx. 187.1 in²

Step-by-step explanation:

Picture this regular polygon as being a hexagon made up of six equilateral triangles of side 12 in.  We find the area of one such triangle and then multiply that by 6 to obtain the total area of the hexagon.

One such equilateral triangle has three sides all of length 12 in, and all the interior angles are 60°.  The height of one such triangle is

h = (12 in)sin 60°, or

                  √3

h = (12 in) -------- = 6√3 in

                     2

So, with base 12 in and height 6√3 in, the area of one such equilateral triangle is

A = (1/2)(12 in)(6√3 in) = 36√3 in²

and the total area of the hexagon is 6(36)√3 in², or approx. 187.1 in²

5 0
3 years ago
The sum of two consecutive odd intergers is 92
frutty [35]

Answer:

45,47

Step-by-step explanation:

(x)+(x+2)=92

= 2x+2=92

=2x=90

x=45

x+2=47

8 0
3 years ago
Read 2 more answers
Use the grouping method to factor x3 + x2 + 3x + 3
Alex

Answer:

8x +3

Step-by-step explanation:

Just collect the like terms, like terms have the same variable. So in this case, 2x, 3x, 3x all share the variable x, so we can add it together.

So when simplified:

2x +3x + 3x+ 3 = 8x +3

Hope this helped,

Cate

4 0
3 years ago
Read 2 more answers
The diagonals of quadrilateral EFGH intersect at D(?3,4). EFGH has vertices at E(3,7) and F(?4,5). What must be the coordinates
Katen [24]

Answer:

  G(3, 1), H(2, 3)

Step-by-step explanation:

When D is the midpoint of EG, it means ...

  D = (E + G)/2

or

  G = 2D -E = 2(3,4) -(3,7) = (2·3-3, 2·4-7) = (3, 1)

Likewise, H is ...

  H = 2D -F = 2(3,4) -(4,5) = (2·3-4, 2·4-5) = (2, 3)

5 0
3 years ago
Construct a frequency distribution and a frequency histogram for the data set using the indicated number of classes. Describe an
elena-s [515]

Answer and Explanation:

Number of classes = 8

    Highest value =2300

  Lowest value = 1250

Class width= highest value – lowest value / number of classes

               = 2300 – 1250/8

                = 131.25 = 132

So, we can write class as 1250+132=1382

Class                                        frequency

1250-1382                                 2

1382-1514                                 3

1514-1646                                 6

1646-1778                                 2

1778-1910                                 3

1910-2042                                 2

2042-2174                                 1

2174-2306                                 1

8 0
2 years ago
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