Question

The teacher asked 4 students to measure 4 different objects. The table shown represents their measurements. Which student had the largest percent error?

Answer 1

Answer:

Student #4

Step-by-step explanation:

The formula for percentage error is given below. We will use this formula for all the four students and figure out whose error is the most.

Percentage Error =  $|\frac{MeasuredValue-ActualValue}{ActualValue}|*100$

• For student 1:

% Error =  $|\frac{49-50}{50}|*100\\=|-0.02|*100\\=(0.02)(100)\\=2$

• For student 2:

% Error =  $|\frac{25.5-25}{25}|*100\\=|0.02|*100\\=(0.02)(100)\\=2$

• For student 3:

% Error =  $|\frac{7.5-8}{8}|*100\\=|-0.0625|*100\\=(0.0625)(100)\\=6.25$

• For student 4:

% Error =  $|\frac{2.1-1.6}{1.6}|*100\\=|0.3125|*100\\=(0.3125)(100)\\=31.25$

Clearly, 31.25% error of student #4 is the highest.

Answer 2

The correct answer is student four because it was off the most