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elena-s [515]
3 years ago
8

What are facts using mathematical terms for second grade

Mathematics
1 answer:
Sav [38]3 years ago
5 0
Just tell them to write down simple math problems and they will get it easier for them.

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If Dorie devotes the same number of hours to studying for these three classes each week, what is the total number of hours Kathl
expeople1 [14]

Answer:

The answer is 17.2 hours

Step-by-step explanation: Because first you add all hours together (which is 86/15) then multiple it by 3 (week) which is 86/5 = 17.2 hours

4 0
2 years ago
Tran had $40 saved for a new bike. The next week, he had $68. At what rate of change did Tran’s savings grow?
Novay_Z [31]

You have to subtract $40 from $68 make sure the larger number is in the front. If you did that all you would get $28.

5 0
4 years ago
Item 7
topjm [15]

Answer:8,5 recirpoal is 5,8

Step-by-step explanation:

8 0
3 years ago
Nuts.com sells raw almonds for $10 per pound and roasted pistachios for $12 per pound. Christopher spends $70, before taxes and
sp2606 [1]

Christopher purchased 2.8 pounds of almonds and 3.5 pounds to roasted pistachios.

Step-by-step explanation:

Cost of almonds per pound = $10

Cost of roasted pistachios = $12

Total amount spent = $70

Weight of nuts = 6.3

Let,

Weight of almonds = x

Weight of roasted pistachios = y

According to given statement;

x+y=6.3   Eqn 1

10x+12y=70   Eqn 2

Multiplying Eqn 1 by 10

10(x+y=6.3)\\10+10y=63\ \ \ Eqn\ 3

Subtracting Eqn 3 from Eqn 2;

(10x+12y)-(10x+10y)=70-63\\10x+12y-10x-10y=7\\2y=7

Dividing both sides by 2

\frac{2y}{2}=\frac{7}{2}\\y=3.5

Putting y=3.5 in Eqn 1

x+3.5=6.3\\x=6.3-3.5\\x=2.8

Christopher purchased 2.8 pounds of almonds and 3.5 pounds to roasted pistachios.

Keywords: linear equations, elimination method

Learn more about elimination method at:

  • brainly.com/question/11007026
  • brainly.com/question/11207748

#LearnwithBrainly

8 0
3 years ago
HELP, I’M STUCK !
vaieri [72.5K]

Since P(<em>X</em> = <em>x</em>) = 0.3 for all 0 ≤ <em>x</em> ≤ <em>α</em>, we have

\displaystyle\int_{-\infty}^\infty P(X=x)\,\mathrm dx=1\implies0.3\int_0^\alpha\mathrm dx=0.3\alpha=1\implies\alpha=\dfrac{10}3

So,

P(X>2) = \displaystyle\int_2^\infty P(X=x)\,\mathrm dx=0.3\int_2^{\frac{10}3}\mathrm dx

P(X>2)=0.3\left(\dfrac{10}3-2\right)=\boxed{\dfrac25}

6 0
3 years ago
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