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elena-s [515]
3 years ago
8

What are facts using mathematical terms for second grade

Mathematics
1 answer:
Sav [38]3 years ago
5 0
Just tell them to write down simple math problems and they will get it easier for them.

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Ok maths experts ,here is your trigonometric question
EleoNora [17]

Answer:


Step-by-step explanation:

i don't take trig :/

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3 years ago
2(3 + 4x) = 8x + 6<br> How Many solutions?
Mrrafil [7]

Answer:

Infinite number of solutions

Step-by-step explanation:

2(3 + 4x) = 8x + 6\\6 + 8x = 8x+6\\8x-8x=6-6\\0=0

For any value of x, both equations are equal to each other because both sides are identical

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3 years ago
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I have no idea what I am doing. Here is one of my problems,
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You need to set up a linear graph. One side with gallons and the other with dollars. Point 1 will be at (1500, 2.10). Point 2 (1300, 2.95). Draw a straight line through these points in your graph and your graph will then give you the answers to your other questions.
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ILL GIVE BRAINLIEST! HELP!
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3 years ago
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Assume that there are an equal number of births in each month so that the probability is that a person chosen at random was born
NikAS [45]

Answer:

0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have a birthday in May, or they do not. The probability of a person having a birthday in May is independent of any other person. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability of a person being in May:

May has 31 days in a year of 365. So

p = \frac{31}{365} = 0.0849

Group of 20 friends:

This means that n = 20

What is the probability that at the May celebration, exactly two members of the group have May birthdays?

This is P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{20,2}.(0.0849)^{2}.(0.9151)^{18} = 0.2773

0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays

3 0
3 years ago
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