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2 years ago

What are facts using mathematical terms for second grade

Mathematics

1 answer:

Sav [38]2 years ago

5 0

Just tell them to write down simple math problems and they will get it easier for them.

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On this corrdinate plane UVW has been transformed to form image U’ V’ W’.

egoroff_w [7]

Answer:

Step-by-step explanation:

Translate the image 2 units right and 1 unit up. Then rotate the image 180°.

Take the coordinate W, it is at (2, 4).

Translate 2 units right (add 2 to the x coordinate) and 1 up (add 1 to the y coordinate)

(2, 4) ------> (2 + 2, 4 + 1) -------> (4, 5)

A rotation of 180° (doesn't matter the direction) makes the coordinates their opposites. Positives become negatives and negatives become positive.

(4, 5) -------> (-4, -5)

8 0

2 years ago

Draw a number line from –2 to 2. Put tick marks every one-tenth unit. Graph a point with the given coordinate.

shusha [124]

Okay! I drew the graph and I got Point Q is 0.1 unit to the right of 1.

Knowing the order of the numbers is the best way to get the answer.

7 0

3 years ago

If a case of chips has 27 bags in it. How many cases would they need for 410 bags of chips?

kodGreya [7K]

Answer:

they would need 15 cases for 410 bag of chips

Step-by-step explanation:

410/7= about 15

3 0

2 years ago

20 points helppppppppppppppppppppppppppppp PLZZ anyone solve this ASAP

Sonja [21]

Answer:

$cos^{-1}(cos\frac{ 7π}{6})=cos^{-1}(cos\frac{7*180}{6})$

$cos^{-1}(cos{210})$

$cos^{-}(cos(180+30))$

[since in third quadrant cos 30=- $\frac{\sqrt{3}}{2}]$

$cos^{-}(- \frac{\sqrt{3}}{2})$

:150°or $\frac{5π}{6}$

150°or  $\frac{5π}{6}$ is a required answer.

4 0

2 years ago

A cement walk 3 ft wide is placed around the outside of a rectangular garden plot that is 20ft by 30ft. Find the cost of the wal

Inessa05 [86]

Let us calculate the area of the walk.

Since the width of the walk is 3 feet, and the walk will be placed all the 4 sides,

Length of the plot including walk = 20 + (2 × 3) = 20 + 6 = 26 feet.

Breadth of the plot including walk = 30 + (2 × 3) = 36 feet.

Area of the plot including walk = 26 × 36 square feet.

Area of the plot = 20 × 30 square feet.

Area of the walk = (26 × 36) - (20 × 30)

= 936 - 600

= 336 square feet.

= $\frac{336}{3(3)}$ square yards

= 37.3 square yards

Cost of the walk per square yard = $12.25.

Therefore, total cost of the walk = 12.25 × 37.3 = $456.92.

7 0

3 years ago