Boyle Law says “the pressure of fixed amount of ideal gas which is at constant temperature is
inversely proportional to its volume".<span>
P = 1/V
<span>Where, P is pressure of the ideal gas and V is volume of the ideal gas.</span>
<span>For two situations, this law can be added as;
P</span>₁V₁ = P₂V₂<span>
</span><span>14 lb/in² x V₁ = 70 lb/in² x 500 mL</span><span>
</span><span>V₁ =
2500 mL</span><span>
Hence, the needed volume of atmospheric air = 2500
mL
<span>Here, we made two </span>assumptions. They are,
1. The
atmospheric air acts as ideal gas.
2.
Temperature is a constant.
<span>We didn't convert the units to SI units since
converting volume and pressure are products of two numbers, they will cut off. </span></span></span>
Xe !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
0.384g/l
Explanation: the density version of the ideal gas law is pm=drt
in which p= pressure, m=molar mass,d=, density, r= to a constant which is 0.08206, and t=temperature so just input the values
PM=DRT. so to find d the formula would be D=RT\PM
D=<u>0.08206*242.5</u>
0.7311*70.90
D=0.384g/l
Answer:
a) Equilibrium shifts in forward direction.
Explanation:
If pressure is increased, equilibrium shifts to the side with the fewer moles of gas.
There are 4 moles of gas in the reactants and 2 moles of gas in the products.
The equilibrium will shift in the forward direction towards the products.
Hope that helps.
