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3 years ago

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How would you find the area of the shaded region?

1 answer:

Whitepunk [10]3 years ago

3 0

Answer:

The Area of the shaded region = (Area of the largest circle) – (Area of the circle with radius 3) – (Area of the circle with radius 2). Whatever is left over is the shaded region. The diameter of the largest circle is 10, so its radius is 5 and thus its area is 25π. SO do this in that problem and you will get the answer.

Step-by-step explanation:

pls give me brainliest

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Classify each angle.

serg [7]

Answer:

∠MDP = 90° = Right angle

∠MDP = 180° = Straight angle

∠ODM = 90° = Right angle

∠OND = Not an angle

∠NDO = 90° = Right angle

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∠PMN = Not an angle

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∠PDN = 90° = Right angle

If my answer helped, please mark me as the brainliest!

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3 years ago

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Expand & simplify<br> 5<br> (<br> p<br> +<br> 5<br> )<br> +<br> 6<br> (<br> p<br> +<br> 6<br> )

Aloiza [94]

5(p+5) + 6(p+6)

First step: Distribute (PEMDAS --> Parenthesis)

5p + 25 + 6p + 36 Now, combine like terms

11p + 61

Thus, the answer is 11p + 61

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2 years ago

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The measure of an exterior angle of a triangle is zº. The measure of the adjacent interior angle is at least twice 2". Which of

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2 years ago

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Scorpion4ik [409]

Answer:

a. $5 \frac{21}{40}$

b. $\frac{1}{42}$

Step-by-step explanation:

$a. \: 12 \frac{2}{5} - 6 \frac{7}{8}$

$\frac{62}{5} - \frac{55}{8}$

$\frac{62}{8} \times \frac{8}{8} - \frac{55}{8} \times \frac{5}{5}$

$\frac{62 \times 8 - 55 \times 5}{40}$

$\frac{221}{40}$

$5 \frac{21}{40}$

$b. \: \frac{3}{14} - \frac{4}{21}$

$\frac{3}{14} \times \frac{3}{3} - \frac{4}{21} \times \frac{2}{2}$

$\frac{3 \times 3}{42} - \frac{4 \times 2}{42}$

$\frac{1}{42}$

Hope it is helpful....

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3 years ago

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