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nignag [31]
3 years ago
6

Please help, will grant brainliest if correct, need now!!

Mathematics
1 answer:
Mama L [17]3 years ago
3 0

Answer:

- 7

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

\frac{f(b)-f(a)}{b-a}

Here [ a, b ] = [ - 5, - 2 ]

f(b) = f(- 2) = (- 2)² - 4 = 4 - 4 = 0

f(a) = f(- 5) = (- 5)² - 4 = 25 - 4 = 21, thus

average rate of change = \frac{0-21}{-2-(-5)} = \frac{-21}{3} = - 7

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Answer:

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Step-by-step explanation:

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In a random sample of males, it was found that 28 write with their left hands and 210 do not. In a random sample of females, it
Drupady [299]

Answer:

a) Null hypothesis:p_{M} \geq p_{W}  

Alternative hypothesis:p_{M} < p_{W}  

b) z=\frac{0.118-0.125}{\sqrt{0.122(1-0.122)(\frac{1}{238}+\frac{1}{497})}}=-0.271    

c)p_v =P(Z   

d) If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the proportion of men that write with their left hand is NOT significant lower than the proportion of female that write with their left hand

Step-by-step explanation:

1) Data given and notation  

X_{M}=28 represent the number of men that write with their left hand

X_{W}=62 represent the number of women  that write with their left hand

n_{M}=210+28=238 sample of male selected

n_{W}=62+435=497 sample of female selected

p_{M}=\frac{28}{238}=0.118 represent the proportion of men  that write with their left hand

p_{W}=\frac{62}{497}=0.125 represent the proportion of women that write with their left hand

\alpha=0.05 represent the significance level

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the rate of left-handedness among males is less than that among females , the system of hypothesis would be:  

Null hypothesis:p_{M} \geq p_{W}  

Alternative hypothesis:p_{M} < p_{W}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}   (1)

Where \hat p=\frac{X_{M}+X_{W}}{n_{M}+n_{W}}=\frac{28+62}{238+497}=0.122

3) Calculate the statistic

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.118-0.125}{\sqrt{0.122(1-0.122)(\frac{1}{238}+\frac{1}{497})}}=-0.271  

4) Statistical decision

We have a significance level provided \alpha=0.05, and now we can calculate the p value for this test.  

Since is a one left side test the p value would be:  

p_v =P(Z  

If we compare the p value and the significance level given \alpha=0.05, 0,1,0.15 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the proportion of men that write with their left hand is NOT significant loer than the proportion of female that write with their left hand .  

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Miss Hamel asked 200 students to select their favorite sport and recorded their results in the bar graph below.
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Step-by-step explanation:

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Martha is late for class, so she races her 75 kg body up a 4.0 meter flight of stairs in only 2.3 seconds. What is Martha’s powe
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Answer:

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Step-by-step explanation:

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*It is worth noting that F must be parallel to the distance travelled. If it is perpendicular, no work is done, and if it is at an angle, find the parallel component and use that for F.

In this case, the force applied must counter the force of gravity on Martha, which is given by F_g=mg, where m = Martha's mass and g = gravitational constant 9.8 m/s/s. Therefore, F_g=75\cdot 9.8=735\text{ N}. Since she raises her body 4.0 meters, the work done must be W=Fd=735\cdot 4=2940\text{ J}.

Since power is equal to work over time and t = 2.3 seconds, we have:

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