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7nadin3 [17]
2 years ago
13

What is the value of the expression (3a-b)/(6(b+a)) when a = 4 and b = -2? Show your work to support your answer.

Mathematics
1 answer:
olga nikolaevna [1]2 years ago
6 0

Answer:

1\frac{1}{6} or 1.166 Repeating

Step-by-step explanation:

This is a very simple equation!

First you write it out

\frac{3a-b}{6(b+a)}

Now you plug in your values.

a = 4

b= -2

So.

\frac{3(4) - (-2)}{6(-2+4)}

Now, follow PEMDAS

3 (4) = 12

12 - (-2) is the same as 12+2 Which equals 14

Now you have...

\frac{14}{6(-2+4)}

-2 + 4 = 2

6 (2) = 12

Final Fraction is

\frac{14}{12}

Which can be reduced to

\frac{7}{6}

or

1.166 (repeating)

Hope this helps!

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Step 2

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