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7nadin3 [17]
3 years ago
13

What is the value of the expression (3a-b)/(6(b+a)) when a = 4 and b = -2? Show your work to support your answer.

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
6 0

Answer:

1\frac{1}{6} or 1.166 Repeating

Step-by-step explanation:

This is a very simple equation!

First you write it out

\frac{3a-b}{6(b+a)}

Now you plug in your values.

a = 4

b= -2

So.

\frac{3(4) - (-2)}{6(-2+4)}

Now, follow PEMDAS

3 (4) = 12

12 - (-2) is the same as 12+2 Which equals 14

Now you have...

\frac{14}{6(-2+4)}

-2 + 4 = 2

6 (2) = 12

Final Fraction is

\frac{14}{12}

Which can be reduced to

\frac{7}{6}

or

1.166 (repeating)

Hope this helps!

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╦────────────────────────────╦

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Read 2 more answers
Consider the surface f (x comma y comma z )f(x,y,z)equals=negative 2 x squared plus 2 y squared minus 3 z squared plus 3 equals
trapecia [35]

Answer:

a) (8,8,-6)

b) 4x+4y+3z = -3

Step-by-step explanation:

a)

The surface is given by the equation  

f(x,y,z) = 0 where

f(x,y,z)=-2x^2+2y^2-3z^2+3

The gradient of this function is the vector

(\frac{\partial f}{\partial x},\frac{\partial f}{\partial y},\frac{\partial f}{\partial z})=(-4x,4y,-6z)

If we evaluate it in the point P = (-2,2,1) we obtain the point

(8,8,-6)

b)

The vectors with their tails at P are of the form  

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as they must be orthogonal to the gradient, they must be orthogonal to the vector (8,8,6) so their inner product is 0

(-2-x,2-y,1-z)\cdot(8,8,6)=0\Rightarrow -16-8x+16-8y+6-6z=0\Rightarrow 4x+4y+3z=-3

and the equation of the desired plane is

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3 0
4 years ago
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