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emmainna [20.7K]
3 years ago
14

The expression -7y is a

Mathematics
2 answers:
myrzilka [38]3 years ago
8 0

the expression-7y is a equation

9966 [12]3 years ago
5 0

Answer:

Step-by-step explanation:

The expression ,"-7y is a" is an equation because the expression included the word is: equal to.

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What is this fraction?
e-lub [12.9K]

\sqrt{361}=19\ \text{because}\ 19^2=361

\dfrac{361}{\sqrt{361}}=\dfrac{361}{19}=19

19 is

A: real

B: whole

C: integer

D: rational

5 0
3 years ago
Maria walked 3 km west and 4 km south calculate how far she is from her starting point.
Rufina [12.5K]

Answer:

5 km

Step-by-step explanation:

We are given the distances walked by Maria;

  • 3 km west and 4 km south

We are required to determine the displacement from her starting point;

  • We are going to use Pythagoras's theorem;

a² + b² = c²

Taking, the distances towards south and towards west as the legs of the triangle;

Then, c² = 3² + 4²

               = 25

         c  = √25

            = 5 km

Therefore, the displacement from the starting point is 5 km

8 0
3 years ago
Question :
Elza [17]

Answer:

C) 405.3 ft

Step-by-step explanation:

A triangle is a polygon with three angles and three sides. Types of triangle are scalene, isosceles, equilateral, right angled triangle.

Given a triangle with angles A, B, C and the corresponding sides directly opposite to the angles as a, b, c. The sine rule states that:

\frac{a}{sin(A)}= \frac{b}{sin(B)} =\frac{c}{sin(C)}

In the triangle formed by point C, ship B and ship A, we have ∠A = 82°, ∠B = 78°, c = AB = 140 ft. Hence:

∠A + ∠B + ∠C = 180° (sum of angles in a triangle)

82 + 78 + ∠C = 180

∠C + 160 = 180

∠C = 20°

Using sine rule:

\frac{c}{sin(C)}=\frac{a}{sin(A)}\\\\\frac{140}{sin(20)}=\frac{a}{sin(82)}\\\\a=    \frac{140*sin (82)}{sin(20)}\\\\a=405.3\ ft

a =  distance from Ship B to the signal fire at point C

8 0
2 years ago
All the answers please
Nata [24]

Answer:

6. 4

7. 40

8. 10

9. 4

10. 21

Step-by-step explanation:

6 0
3 years ago
Show that in any group of 101 people there are at least two persons having the same number friends (It is assumed that if a pers
vladimir1956 [14]

Answer:

Step-by-step explanation:

Let us assume that if possible in the group of 101, each had a different number of friends.  Then the no of friends 101 persons have 0,1,2,....100 only since number of friends are integers and non negative.

Say P has 100 friends then P has all other persons as friends.  In this case, there cannot be any one who has 0 friend.  So a contradiction.  Hence proved

Part ii: EVen if instead of 101, say n people are there same proof follows as

if different number of friends then they would be 0,1,2...n-1

If one person has n-1 friends then there cannot be any one who does not have any friend.

Thus same proof follows.

7 0
3 years ago
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