The volume of the Apple iPad Mini 2 is 12.561 in³.
The new volume of the Pear-Apple is 24.53 in³.
The new volume of the Pear-Apple is 5.3in³.
The scale factor to have a volume that is half that of the iPad Mini is 0.79.
The scale factor to have a volume that is double that of the iPad Mini is 1.26
<h3 /><h3>What is the volume of the Apple iPad Mini 2?</h3>
Volume = length x width x height
7.9 x 5.30 x 0.30 = 12.561 in³
<h3>What is the volume after the scale factors are applied?</h3>
Dimensions after the 1.25 scale factor is applied: (1.25 x 7.9) x (1.25 x 5.30) x (1.25 x 0.3)
= 9.875 x 6.625 x0.375 = 24.53 in³
Dimensions after the 0.75 scale factor is applied: (0.75 x 7.9) x (0.75 x 5.30) x (0.75 x 0.3)
= 5.925 x 3.975 x 0.225 = 5.3in³
Scale factor to have a volume that is double that of the iPad Mini : 
= 1.26
Scale factor to have a volume that is half that of the iPad Mini : 
= 0.79
To learn more about scale drawings, please check: brainly.com/question/26388230
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Answer:
(-2, 20)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = -7x + 6
y = -10x
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em> [1st Equation]: -10x = -7x + 6
- [Addition Property of Equality] Add 7x on both sides: -3x = 6
- [Division Property of Equality] Divide -3 on both sides: x = -2
<u>Step 3: Solve for </u><em><u>y</u></em>
- Substitute in <em>x </em>[2nd Equation]: y = -10(-2)
- Multiply: y = 20
X + 3 = 8
x = 8 - 3
x = 5 <=
The answer is negative 2.5 why because...
Hello,
2x^3+14x^2+6x+42=2x^2(x+7)+6(x+7)
=(x+7)(2x²+6)
=2(x+7)(x²+3) in IR.
or In C 2(x+7)(x-i√3)(x+i√3)
