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3 years ago

Dos angulos son congruentes si tienen la misma amplitud

Mathematics

1 answer:

Margarita [4]3 years ago

6 0

Answer:

true

Step-by-step explanation:

2 angles are congruent when they they have the same measure

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Omar has 2-5/8 cups of dough to make dumplings. If he uses 3/16 cup of dough for each dumpling, how many whole dumplings can Oma

Arte-miy333 [17]

Answer:

The number of whole dumpling does Omar make is 14 .

Step-by-step explanation:

Given as :

The number of cups does Omar has to make dumplings = x = 2 $\dfrac{5}{8}$

i.e x = $\dfrac{16 + 5}{8}$

or, x = $\dfrac{21}{8}$

Again

The number of cups uses for each dumpling = y = $\dfrac{3}{16}$

i.e y = $\dfrac{3}{16}$

Let The number of whole dumpling does Omar make = z

So, number of whole dumpling does Omar make = $\dfrac{\textrm number of cups does Omar has to make dumplings}{number of cups uses for each dumpling }$

Or, z = $\dfrac{x}{y}$

Or, z = $\frac{\frac{21}{8}}{\frac{3}{16}}$

Or, z = $\frac{21\times 16}{8\times 3}$

∴ z = 7 × 2

i.e z = 14

So, The number of whole dumpling does Omar make = z = 14

Hence, The number of whole dumpling does Omar make is 14 . Answer

8 0

3 years ago

CORRECT FAST ANSWERS!! Brainliest!

Rom4ik [11]

Answer:

its d

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

2x^3=28<br><br> find the exact solution for x

Alborosie

Answer:

The answer to your question is: x = 2.41

Step-by-step explanation:

2x³ = 28

x³ = 28/2

x³ = 14

x = ∛14

x = 2.41

6 0

3 years ago

What is an expression equivalent to -4(-6m - 7)

nekit [7.7K]

Answer: 24m+28

Step-by-step explanation:

you would distribute the -4 threw eveything

so it would be 24m+28

6 0

3 years ago

Prove that tan 10+tan 70'+taniou = tanio tanfo'tam 1oo.

Galina-37 [17]

Question:

Prove that:

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$

Answer:

Proved

Step-by-step explanation:

Given

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$

Required

Prove

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$

Subtract tan(10) from both sides

$- tan(10)+tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)$

$tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)$

Factorize the right hand size

$tan(70) + tan(100) = -tan(10)(-tan(70). tan(100) + 1)$

Rewrite as:

$tan(70) + tan(100) = -tan(10)(1-tan(70). tan(100))$

Divide both sides by $1-tan(70). tan(100)$

$\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = \frac{-tan(10)(1-tan(70). tan(100))}{1-tan(70). tan(100))}$

$\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10)$

In trigonometry:

$tan(A + B) = \frac{tan(A) + tan(B)}{1 - tan(A)tan(B)}$

So:

$\frac{tan(70) + tan(100)}{1 - tan(70)tan(100)}$ can be expressed as: $tan(70 + 100)$

$\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10)$ gives

$tan(70 + 100) = -tan(10)$

$tan(170) = -tan(10)$

In trigonometry:

$tan(180 - \theta) = -tan(\theta)$

So:

$tan(180 - 10) = -tan(10)$

Because RHS = LHS

Then:

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$ has been proven

6 0

3 years ago