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UkoKoshka [18]
2 years ago
6

Which of the following systems has equations that are dependent?

Mathematics
1 answer:
s344n2d4d5 [400]2 years ago
4 0

Answer : number 4 is a dependent system
Explanation:
If we look at number 4
2x+2y=6 , y= -x+3
2(x+y)=6
x+y=6/2=3
y=-x+3

Now we see that the two equation have the same slope (-x) and the same y intercept (+3) we can clearly say that these 2 equation are dependent because it has infinite solution
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Please help !
Serjik [45]

To move a graph vertically and/or horizontally around the coordinate plane is called shifting or translation.


Shifting is simply moving the graph. Horizontal shift would be moving/shifting the graph to left or right. Vertical shift would be moving/shifting the graph to up or down.

There are another transformation methods that involve a more complex equation than shifting like mirroring or rotating.


4 0
2 years ago
pat and tim work together at a pizzeria, Pat can fold 30 pizza boxes per minute and tim can fold 20 pizza boxes per minute. Work
Marina CMI [18]

Step-by-step explanation:

1 min = 60 sec

Boxes both can fold per min = 30 + 20 = 50

No of boxes to fold = 200

Time taken in sec = 200 ÷ 50 = 4 min = 60 x 4 = 240 sec

5 0
2 years ago
What is the value of root 12+root 12+root12....<br> ...............to infinite
Effectus [21]
X=root(12+root(12+root(...)))
x^2=12+root(12+root(12+root(...)))
x^2=12+x
x^2-x-12=0
(x+3)(x-4)=0
X=4
7 0
3 years ago
16.437 rounded to the neatest tenth is 16.4 true or false
Ainat [17]
Answer=True

When rounding 16.437 to the nearest tenth, we need to look to the hundreds place.

16.437

The number 3 is in the hundreds place

The rules of rounding are:

If the number is 5 or greater, then you round up.

If the number is 4 or less, Then you round down.

Since 3 is less than 4, we would round down. So...

16.437 becomes 16.4
7 0
2 years ago
Read 2 more answers
A spinner has equal regions numbered 1 through 20. What is the probability that the spinner will stop on an odd number or a mult
klio [65]

Answer:

<em>Probability that the spinner will stop on an odd number or a multiple of 5 is </em><em>0.6</em>

Step-by-step explanation:

Probability = \frac{Required outcomes}{Total possible outcomes}

We are given the equal regions numbered from 1 through 20 which means that our total possible outcomes are 20

<em>Total possible outcomes: 20</em>


<em>Outcomes that spinner will stop on an odd number, n(Odd): 10</em>

1, 3, 5, 7, 9, 11, 13, 15, 17, 19

Probability of spinner stoping on Odd number:

P(Odd) = \frac{n(Odd)}{Total} = \frac{10}{20} = \frac{1}{2} = 0.5


Outcomes that spinner will stop on a multiple of 5, n(5): 4

5, 10, 15, 20

Probability of spinner stoping on multiple of 5:

P(5) = \frac{n(5)}{Total} = \frac{4}{20} = \frac{1}{5} = 0.2

Odd numbers which are a multiple of 5 are: 5 and 15

So,

P(Odd and 5) = \frac{2}{20}=\frac{1}{10}=0.1

Thus Probability of spinner stopping at odd number or a multiple of 5 becomes:

P(Odd or 5) = P(Odd) + P(5) - P(Odd and 5) = 0.5 + 0.2 - 0.1 = 0.6

7 0
3 years ago
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