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Colt1911 [192]
2 years ago
14

There is a free prize drawing in a shopping mall. There are some youngsters and older people. The result of the number of winnin

g people is shown below. Which group had a higher % of winners between youngsters and older people?
- 30 older people won washing machines out of the 60 older people. - 45 youngsters won washing machines out of the 60 youngster.
Mathematics
2 answers:
serg [7]2 years ago
8 0

Answer:

There is a free prize drawing in a shopping mall. There are some youngsters and older peoples. The result of the number of winning people is shown below.

Which grow had highest % of winning between youngster and older people? - 30 older people won washing machines out of the 60 older people. - 45 youngsters won washing machines out of the

Scilla [17]2 years ago
5 0

Answer:

the guy or girl up top is right

Step-by-step explanation:

sorry i could'ent help but that person is completely right in i will correct if wrong

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Given that (-4,2) is on the graph of f(x) find the corresponding point for the function -1/2f(x)
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Answer:

The corresponding point is (-4.-1)

Step-by-step explanation:

we know that

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so

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-(1/2)f(x)=-(1/2)*2=-1

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PIT_PIT [208]

Answer:

Y=-4/2 + 6

Step-by-step explanation:

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3 years ago
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The proportion of households in a region that do some or all of their banking on the Internet is 0.31. In a random sample of 100
Alenkasestr [34]

Answer:

Approximate probability that the number of households that use the Internet for banking in a sample of 1000 is less than or equal to 130 is less than 0.0005% .

Step-by-step explanation:

We are given that let X be the number that do some or all of their banking on the Internet.

Also; Mean, \mu = 310/1000 or 0.31   and  Standard deviation, \sigma = 14.63/1000 = 0.01463 .

We know that Z = \frac{X-\mu}{\sigma} ~ N(0,1)

Probability that the number of households that use the Internet for banking in a sample of 1000 is less than or equal to 130 is given by P(X <= 130/1000);

 P(X <=0.13) = P( \frac{X-\mu}{\sigma}  <= \frac{0.13-0.31}{0.01463} ) = P(Z <= -12.303) = P(Z > 12.303)

Since this value is not represented in the z table as the value is very high and z table is limited to x = 4.4172.

So, after seeing the table we can say that this probability is approximately less than 0.0005% .

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3 years ago
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1.50
------- = 1 can
3 cans


1.50
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8 0
3 years ago
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