Question

Please find the solution set of x+3>19-3x, where x is a real number​

Answer 1

Answer:

$x >4$

Step-by-step explanation:

$x+3>19-3x$

Add 3x and -3 on both parts.

$x+3+3x-3>19-3x+3x-3$

Combine like terms.

$x+3x>16$

$4x >16$

Divide 4 on both parts.

$\frac{4x}{4} > \frac{16}{4}$

$x >4$