Answer: 0.31 or 31%
Let A be the event that the disease is present in a particular person
Let B be the event that a person tests positive for the disease
The problem asks to find P(A|B), where
P(A|B) = P(B|A)*P(A) / P(B) = (P(B|A)*P(A)) / (P(B|A)*P(A) + P(B|~A)*P(~A))
In other words, the problem asks for the probability that a positive test result will be a true positive.
P(B|A) = 1-0.02 = 0.98 (person tests positive given that they have the disease)
P(A) = 0.009 (probability the disease is present in any particular person)
P(B|~A) = 0.02 (probability a person tests positive given they do not have the disease)
P(~A) = 1-0.009 = 0.991 (probability a particular person does not have the disease)
P(A|B) = (0.98*0.009) / (0.98*0.009 + 0.02*0.991)
= 0.00882 / 0.02864 = 0.30796
*round however you need to but i am leaving it at 0.31 or 31%*
If you found this helpful please mark brainliest
Answer:
Step-by-step explanation:
Given
To express as a rational number with 91 on the denominator.
91 ÷ 7 = 13
Thus multiply the numerator and denominator by 13, that is
=
Answer:
55
Step-by-step explanation:
difference=8-5=3
if difference is 3 Cole bends=5 times
if difference is 33 Cole bends=(5/3)×33=55 times
The best way to do this is to set up a proportion
2 5
--- = ----
5 x
then cross multiply and divide
5 times 5=25/2=12.5
he would move 12.5 feet in 5 hours
I hope I've helped!
