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kykrilka [37]
3 years ago
14

I need 12 and 13 plzzz

Mathematics
1 answer:
sergey [27]3 years ago
5 0
Solution
2,0,3
Not a solution
15,4,7

True
True
False
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Answer:

Given points

  • A = (2, 1)
  • B = (4, 3)
  • C = (5, 3)
  • D = (6, 1)

<h3><u>Part (a)</u></h3>

See attached

<h3><u>Part (b)</u></h3>

Trapezoid

<h3><u>Part (c)</u></h3>

To dilate ABCD with a dilation center at (0,0) and a dilation factor of 4, multiply the x and y coordinates of ABCD by sf 4:

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  • B' = (16, 12)
  • C' = (20, 12)
  • D' = (24, 4)

<h3><u>Part (d)</u></h3>

<u />\begin{aligned}\textsf{Area of Trapezoid}& =\dfrac{1}{2}(a+b)h\\\implies \textsf{Area of A'B'C'D'}& =\dfrac{1}{2}((x_{D'}-x_{A'})+(x_{C'}-x_{B'}))(y_{B'}-y_{A'})\\& = \dfrac{1}{2}((24-8)+(20-16))(12-4)\\& = \dfrac{1}{2}(20)(8)\\& = 80\: \sf units^2\end{aligned}

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2 years ago
4. If the sides of a square measure 9V3 units, then find the length of the diagonal.
Nitella [24]

Answer:

Step-by-step explanation:

To find the diagonal, use Pythagorean theorem,

diagonal² = side² + side²

                = (9√3)² + (9√3)²

                = 9²(√3)² + 9²(√3)²

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                = 243 + 243

                 = 486

diagonal = √486 = 22.05 units

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Step-by-step explanation:

                 

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