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True [87]
3 years ago
10

Please help im 25% blind

Mathematics
1 answer:
FrozenT [24]3 years ago
5 0

Answer:

c

Step-by-step explanation: all you have to do is work it out

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Solve for y- 6y-1.5x=8
VARVARA [1.3K]

6y-1.5x=8\qquad\text{add 1.5x to both sides}\\\\6y=1.5x+8\qquad\text{divide both sides by 6}\\\\y=\dfrac{1.5}{6}x+\dfrac{8}{6}\\\\y=\dfrac{15}{60}x+\dfrac{4}{3}\\\\\boxed{y=\dfrac{1}{4}x+\dfrac{4}{3}}

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3 years ago
How do I solve: 3w/x=6e
lana [24]
The answer is ×=w/2e.thats it
7 0
3 years ago
Write an expression for "two multiplied by t".<br> Please help!!<br> 10 POINTS
attashe74 [19]

Answer:

2*t

Step-by-step explanation:

That should be it...

Just multiply 2 by t

7 0
3 years ago
Read 2 more answers
Identify the correct corresponding parts
andrey2020 [161]

Answer:

The correct corresponding part is;

\overline {CB} ≅ \overline {CD}

Step-by-step explanation:

The information given symbolically in the diagram are;

ΔCAB is congruent to ΔCED (ΔCAB ≅ ΔCED)

Segment \overline {CA} is congruent to \overline {CE} ( \overline {CA} ≅ \overline {CE})

Segment \overline {CB} is congruent to \overline {CD} ( \overline {CB} ≅ \overline {CD})

From which, we have;

∠A ≅ ∠E by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∠B ≅ ∠D by CPCTC

Segment \overline {AB} is congruent to \overline {DE} (\overline {AB} ≅ \overline {DE}) by CPCTC

Segment \overline {AE} bisects \overline {BD}

Segment \overline {BD} bisects \overline {AE}

Therefore, the correct option is \overline {CB} ≅ \overline {CD}

3 0
3 years ago
Find the exact value of sin (-270 degrees).
user100 [1]
The exact value of sin (-270) is determined using the calculator in degrees mode. The answer is equal to 1. If the radians mode is used, -270 is equal to -2 pi/3. Hence using the calculator, we can verify that the answer is still 1. The value of -270 matters.
3 0
3 years ago
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