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Semmy [17]
3 years ago
5

What is the volume of a cylinder, in cubic cm, with a height of 7cm and a base diameter of 10cm?

Mathematics
1 answer:
topjm [15]3 years ago
7 0

Answer:

Volume of a Cylinder:

In geometry, a cylinder is a three-dimensional shape with a circular base, a circular top and straight sides. It is the solid figure that you get when you rotate a rectangle about one of its sides. In most cases when we talk about the volume of a cylinder, we are talking about how much liquid it can hold.

The strictly correct way of saying it is "the volume surrounded by a cylinder" - the amount of liquid it holds. But many textbooks simply tell "the volume of a cylinder" to mean the same thing.

Remember that the radius and the height must be in the same units - convert them if necessary.

The resulting volume will be in those cubic units. So if the height and radius are both in centimeters, then the volume will be in cubic centimeters.

The volume of a cylinder is found by multiplying the area of its top or base by its height and is defined as: V = π· r2· h

Example 1: A cylindrical water storage tank has an inside base radius of 7m and depth of 11 m. Find the capacity of the tank in kiloliters (1kl = 1m3).

Solution:

Base radius: r = 7 m

Height: h = 11 m

The water storage tank is in the shape of the cylinder. So using the volume of cylinder formula we can find the volume of it.

V = π· r2· h

V = π· 72· 11

V = 1692.46 m3 = 1692.46 kl

Example 2: Find the volume of a cylinder whose base radius is 6 cm and height is 4 cm.

Solution:

Base radius: r = 6 cm

Height: h = 4 cm

V = π· r2· h

V = 3.14· 62· 4

V = 452.16 cm3

Example 3: If the capacity of a cylindrical tank is 1848 m3 and the diameter of its base is 14 m, find the depth of the tank.

Solution:

Let the depth of the tank be h metres. Then we have:

V = π· r2· h

h = V / π· r2

h = 12 m

Example 4: A conical vessel, whose internal radius and height is 20cm and 50 cm respectively, is full of liquid. Find the height of the liquid if it is put into a cylinder whose base radius is 10 cm.

Solution:

The volume of the vessel is:

V = π ∙ r2 ∙ h / 3

V = π · 202· 50 / 3

V = 20944 cm3

The volume of the liquid is the same no matter it is in the vessel or in the cylinder, therefore we have:

V1 = V2, where V1 is the volume of the vessel and V2 is the volume determined using the formula for a cylinder.

20944 = π · 102 · h

Thus:

h = 20944 / (π · 102)

h = 66.67 cm

Example 5: Find the volume of a right circular cylinder whose curved surface area is 2640 cm2

And the circumference of its base is 66 cm.

Solution:

To begin with we need to determine the base radius using the formula for circular perimeter (circumference).

P = 2 · π ·r

r = P /(2 · π) = 66 / (2 · π) = 10.50 cm

Now we will find the height of the cylinder using the formula for surface area of a cylinder.

SA = P · h

h = SA / P = 2640 / 66 = 40 cm

The volume of the cylinder is therefore:

V = π· r2· h

V = π· 10.502· 40

V =13854.4 cm3

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T what point does the curve have maximum curvature? Y = 7ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as
Nookie1986 [14]

Formula for curvature for a well behaved curve y=f(x) is


K(x)= \frac{|{y}''|}{[1+{y}'^2]^\frac{3}{2}}


The given curve is y=7e^{x}


{y}''=7e^{x}\\ {y}'=7e^{x}


k(x)=\frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}


{k(x)}'=\frac{7(e^x)(1+49e^{2x})(49e^{2x}-\frac{1}{2})}{[1+49e^{2x}]^{3}}

For Maxima or Minima

{k(x)}'=0

7(e^x)(1+49e^{2x})(98e^{2x}-1)=0

→e^{x}=0∨ 1+49e^{2x}=0∨98e^{2x}-1=0

e^{x}=0  ,  ∧ 1+49e^{2x}=0   [not possible ∵there exists no value of x satisfying these equation]

→98e^{2x}-1=0

Solving this we get

x= -\frac{1}{2}\ln{98}

As you will evaluate {k(x})}''<0 at x=-\frac{1}{2}\ln98

So this is the point of Maxima. we get y=7×1/√98=1/√2

(x,y)=[-\frac{1}{2}\ln98,1/√2]

k(x)=\lim_{x\to\infty } \frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}

k(x)=\frac{7}{\infty}

k(x)=0







5 0
3 years ago
Help me worth 25 points
eimsori [14]
Your area is 37, hope this helps.
6 0
4 years ago
Classify the following expression by degree and term: x2y − 7xy + xyz + x
goldfiish [28.3K]
3rd degree polynomial with 4 terms
4 0
3 years ago
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UPS charges $6.00 for the first pound, $1.00 for the second pound, and $0.15 for each additional pound. FedEx charges $4.00 for
Pavlova-9 [17]

Answer:

12 pounds

Step-by-step explanation:

We we need to write equations to represent the situation in this problem.

x=weight of package

UPS cost=6+1+0.15(x-2)

UPS cost=6+1+0.15x-0.3

UPS cost=6.7+0.15x

FedEx cost=4+2+.25(x-2)

FedEx cost=4+2+0.25x-0.5

FedEx cost=5.5+0.25x

Next, we can set the two equations equal to each other to solve for x.

6.7+0.15x=5.5+0.25x

6.7+0.15x-5.5=5.5+0.25x-5.5

1.2+0.15x-0.15x=0.25x-0.15x

1.2/0.1=0.1x/0.1

x=12

It takes 12 pounds for the UPS and FedEx packages to cost the same amount to ship.

8 0
3 years ago
60 POINTS I NEED ANSWER FAST. WILL MARK BRAINLIEST.
Deffense [45]

Answer:

5.2

Step-by-step explanation:

4.3/5.6 = 4/AB

AB = 5.2

4 0
3 years ago
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