Let's define variables:
s = original speed
s + 12 = faster speed
The time for the half of the route is:
60 / s
The time for the second half of the route is:
60 / (s + 12)
The equation for the time of the trip is:
60 / s + 60 / (s + 12) + 1/6 = 120 / s
Where,
1/6: held up for 10 minutes (in hours).
Rewriting the equation we have:
6s (60) + s (s + 12) = 60 * 6 (s + 12)
360s + s ^ 2 + 12s = 360s + 4320
s ^ 2 + 12s = 4320
s ^ 2 + 12s - 4320 = 0
We factor the equation:
(s + 72) (s-60) = 0
We take the positive root so that the problem makes physical sense.
s = 60 Km / h
Answer:
The original speed of the train before it was held up is:
s = 60 Km / h
Assuming you meant 2/3
y=2/3x+1 and (-5,-2)
paralell means same slope
y=mx+b
m=slope
y=2/3x+1
sllope=2/3
point slope
y-y1=m(x-x1)
for slope=m
a point is (x1,y1)
slope=2/3
point=(-5,-2)
y-(-2)=2/3(x-(-5))
y+2=2/3(x+5)
or
y=2/3x+16/3
Answer:
Step-by-step explanation:
Not a Function because : (-20, - 7) and (-20,- 10)
each element must associate with a single
-20 to associate two elements: -10; -7
y=30 x=60 that should be the answer sorry if it isnt
Answer:
y= 2
x
+
2 i think
Step-by-step explanation:
