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Semenov [28]
3 years ago
8

In the following code, what values could be read into number to terminate the while loop? Scanner keyboard = new Scanner(System.

in); System.out.print("Enter a number: "); int number = keyboard.nextInt(); while (number < 100 || number > 500) { System.out.print("Enter another number: "); number = keyboard.nextInt(); }
Computers and Technology
1 answer:
tia_tia [17]3 years ago
3 0

Answer:

The following code read the numbers in the range of 100 through 500.

Explanation:

The following code is written in Java Programming Language.

Here, firstly create a new Scanner object "keyboard" then, declare an integer variable "number" to "keyboard.nextInt()" and the set the loop while and inside it print the message.

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The major objective of this lab is to practice class and object-oriented programming (OOP), and separate files: 1. We will reuse
vovangra [49]

Answer:

Implementation of resistor.cpp

#include "resistor.h"

Ohms::Ohm()

{

// default constructor

voltage=0;

}

Ohms::Ohm( double x) // parameterised constructor

{

voltage = x; // voltage x set to the supply voltage in the private data field called voltage

}

Ohms:: setVoltage(double a)

{

voltage = a;// to set supply voltage in private data field called voltage

}

Ohms::setOneResistance( String s, double p)

{

cin>>p; //enter the resistance value

if(p<=0) // if resistance is less than or equals to 0

return false

else // if re

cin.getline(s);

}

Ohms::getVoltage()

{

return voltage; //return voltage of ckt

}

Ohms::getCurrent()

{

return current; //return current of ckt

}

Ohms:: getNode()

{

return resistors; //return resistors of ckt

}

Ohms::sumResist()

{

double tot_resist = accumulate(resistors.begin(),resistors.end(),0); //std::accumulate function for calculating sum //of vectors and following are the starting and ending points

return tot_resist;

}

Ohms::calcCurrent()

{

if(current <=0) // if current is less than or equal to 0

return false;

else   // if current is greater than 0

return true;

}

Ohms:: calcVoltageAcross()

{

if(voltage<=0) // if voltage is less than or equal to 0

return false;

else //if voltage greater than 0

return true;

}

Explanation:

in the case of main.cpp its simple just make a class object and remember to include resistors.cpp with it for which the second last picture describes the process precisely. (Hint: Use theunit test case functions in the main.cpp).

As you can see node is a structure consisting of member variables, followed by a class Ohms representing a DC circuit.

By looking at these pictures, it is needed to implement the main.cpp and resistor.cpp files. The user defined header file resistor.h already consists of all contents of Class Ohm, struct node. You don't need to modify it in anyway in such case.

8 0
3 years ago
Which of the following processes is not part of the rock cycle?
Leviafan [203]
Igneous rock forced below the Earth's surface where it is turned into sedimentary rock through intense heat and pressure.

This process creates metamorphic rocks, not sedimentary.
3 0
4 years ago
Storing the same data in more than one place is called ______
nadezda [96]
It is called a file!
7 0
3 years ago
Consider the method total below.
evablogger [386]
That code, if it even compiles, won't produce those values with that call.
5 0
3 years ago
Read 2 more answers
Design a program takes as input, X, an unsorted list of numbers, and returns the sorted list of numbers in X. The program must b
Lelechka [254]

Answer:

The program in python is as follows:

def split(X):

   L = []; G = []

   for i in range(len(X)):

       if X[i]>=X[0]:

           G.append(X[i])

       else:

           L.append(X[i])

   L.sort(); G.sort()

   return L,G

X = []

n = int(input("Length of X: "))

for i in range(n):

   inp = int(input(": "))

   X.append(inp)

   

if len(X) == 0 or len(X) == 1:

   print(X)

else:

   X1,X2=split(X)

   newList = sorted(X1 + X2)

   print(newList)

Explanation:

The following represents the split function in the previous problem

def split(X):

This initializes L and G to empty lists

   L = []; G = []

This iterates through X

   for i in range(len(X)):

All elements of X greater than 0 equal to the first element are appended to G

      <em> if X[i]>=X[0]:</em>

<em>            G.append(X[i])</em>

Others are appended to L

<em>        else:</em>

<em>            L.append(X[i])</em>

This sorts L and G

   L.sort(); G.sort()

This returns sorted lists L and G

   return L,G

The main function begins here

This initializes X

X = []

This gets the length of list X

n = int(input("Length of X: "))

This gets input for list X

<em>for i in range(n):</em>

<em>    inp = int(input(": "))</em>

<em>    X.append(inp)</em>

This prints X is X is empty of has 1 element

<em>if len(X) == 0 or len(X) == 1:</em>

<em>    print(X)</em>

If otherwise

else:

This calls the split function to split X into 2

   X1,X2=split(X)

This merges the two lists returned (sorted)

   newList = sorted(X1 + X2)

This prints the new list

   print(newList)

7 0
3 years ago
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