Product of -6/13 and reciprocal of -7/16 is ___________

Answer:RISC(reduced instruction set computer) is the computer used for low level operation by simple command splited into numerous instructions in single clock only and CISC(Complex instruction set computer) is the computer that performs the operation in single instruction.

RISC architecture has hardwired control unit,data cache unit,data path ,instruction cache and main memory as components .CISC architecture persist of control unit,micro program control memory, cache, instruction and data path and main memory.

The differences between RISC and CISC are as follows:-

The instruction in RISC are less and and low complexes while CISC has several number of complex instruction.
The calculation done by RISC are precise and quick whereas CISC has slightly slow calculation processing.
The execution of RISC is faster as compared to CISC.
RISC uses hardware component for implementation of instruction because it does not persist its own memory and CISC implements instructions using its own memory unit .

6 0

2 years ago

The Pentium 4 Prescott processor, released in 2004, has a clock rate of 3.6 GHz and voltage of 1.25 V. Assume that, on average,

Zarrin [17]

Answer:

a) C = 3.2 x 10^-8 F, C = 2.9 x 10^-8 F

b) 10%, 42.86%, 0.11, 0.75

c) 0.849 volts to maintain the same leakage current in the Pentium 4 Prescott Processor. 0.783 Volts to maintain the same leakage current in the Core i5 Ivy Bridge Processor.

Explanation:

For the Pentium 4 Prescott processor:

Clock rate (f) = 3.6 GHz

Voltage (V) = 1.25 V

Static Power Consumption = 10 W

Dynamic Power Consumption = 90 W

For the Core i5 Ivy Bridge processor:

Clock rate (f) = 3.4 GHz

Voltage (V) = 0.9 V

Static Power Consumption (SP) = 30 W

Dynamic Power Consumption (DP) = 40 W

(a) To find the average capacitive loads, use the formula:

DP = (1/2) x C x V² x f

Rearranging:

C = (2 x DP)/(V² x f)

For the Pentium 4 Prescott processor:

C = (2 x 90) / [(1.25)² x 3.6 x 10^9]

C = 3.2 x 10^-8 F

For the Core i5 Ivy Bridge processor:

C = (2 x 40) / [(0.9)² x 3.4 x 10^9]

C = 2.9 x 10^-8 F

(b) Percentage of the total dissipated power comprised by the static power can be found by the formula:

[Static Power/(Static Power + Dynamic Power)] x 100

For the Pentium 4 Prescott Processor:

[10/(90+10)] x 100 = 10%

For the Core i5 Ivy Bridge Processor:

[30/30+40] x 100 = 42.86 %

Ratio of static power to dynamic power for each technology can be computed as:

Pentium 4 Prescott: 10/90 = 0.11

Core i5 Ivy Bridge: 30/40 = 0.75

(c) The total dissipated power can be calculated by:

P = DP + SP

For Static Power we have the formula:

SP = VI where I is the leakage current.

I = SP/V

For Pentium 4 Prescott: I = 10/1.25 = 8A

For Core i5 Ivy Bridge: I = 30/0.9 = 3.33 A

The total disspited power is reduced by 10%, meaning the ratio of new power to old power must be 90% = 0.9. So,

New Power/Old Power = 0.9

For Pentium 4 Prescott:

DP + SP / 100 = 0.9

VI + CV²F = 0.9 x 100

V(8) + (3.2 x 10^-8)V²(3.6 x 10^9) = 90

8V + 115.2V² - 90 = 0

By solving the quadratic equation, we get the positive answer as 0.849. This means that the voltage should be reduced to 0.849 volts to maintain the same leakage current in the Pentium 4 Prescott Processor.

For Core i5 Ivy Bridge:

DP + SP / 70 = 0.9

V(3.33) + (2.9 x 10^-8)V²(3.4 x 10^9) = 70 x 0.9

3.33V +98.6V² -63 = 0

By solving the quadratic equation we get the positive answer as 0.783. This means that the voltage should be reduced to 0.783 Volts to maintain the same leakage current in the Core i5 Ivy Bridge Processor.

6 0

3 years ago

Product of -6/13 and reciprocal of -7/16 is ____________​

Product of -6/13 and reciprocal of -7/16 is ____________