It would have one solution since you know the total number of balls
I'll let <em>h</em> = <em>ax</em>, so the limit is
i.e. the derivative of .
Expand the numerator to see several terms that get eliminated:
So we have
Since <em>h</em> ≠ 0 (because it is approaching 0 but never actually reaching 0), we can cancel the factor of <em>h</em> in both numerator and denominator, then plug in <em>h</em> = 0:
Add 20$ and 25$ and go along the line while adding 25 each time, at the same time do the same for 35$, the answer is the second month
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Answer:
Each octave change requires a doubling of the frequency.
Therefore, one octave above 126.63 is 126.63 * 2 which equals
253.26
Step-by-step explanation: