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3 years ago

Carson buys two apples and three bananas for $3. Raquel buys four apples and eight bananas for $7.

Mathematics

1 answer:

Dima020 [189]3 years ago

3 0

Answer:

apple $0.75 banana $0.50

Step-by-step explanation:

Let a be the price of an apple

Let b be the price of an banana

2a+3b=3 (1)

4a+8b=7 (2)

(1)*2

4a+6b=6 (3)

(3)-(2)

-2b=-1

b=1/2

substitiude into (1)

2a+1.5=3

2a = 1.5

a = 0.75

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Solve this problem : (X-3)^2

krek1111 [17]

Answer:

x^2 - 6x + 9

Step-by-step explanation:

(x - 3)^2

(x - 3)(x - 3)

x^2 - 3x - 3x + 9

x^2 - 6x + 9

7 0

3 years ago

Read 2 more answers

Can someone help? This is hard

Licemer1 [7]

CT=90°

BTA=90°

x=29

CT=37

TA=20

CA=57

Step-by-step explanation:

they say BT is an altitude ( or height) . Altitudes are perpendicular meaning that:

BTC =90°

BTA=90°

Therefore:

(3x+3)°=90°

3x=90-3

3x=87°

x=29

CT:

x+8

=29+8

=37

TA:

x-9

=29-9

=20

CA:

=CT+TA

=37+20

=57

7 0

3 years ago

In 2008, the price of gasoline was $2.79 per gallon. In 2009, the price of gasoline was

ikadub [295]

Answer:

36%

Step-by-step explanation:

line up $ and % data like this:

$2.79 represents 100%

$3.79 represents X%

cross multiply

X*2.79 = 3.79*100

divide both sides by 2.79

X= 3.79*100 / 2.79 ≈ 136%

so it increased 36%

7 0

3 years ago

In 1994, the General Social Survey had a question that asked its participants (that currently smoked) if they had ever tried to

Roman55 [17]

Answer:

0.8239 is the population proportion of participants that tried quitting smoking.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 142

Participants that tried quitting smoking = 117

Parameter:

A parameter is a numerical value that describes a population.

Population proportion can be calculated as:

$p = \dfrac{x}{n} \\\\p= \dfrac{117}{142} \\\\p= 0.8239$

0.8239 is the population proportion of participants that tried quitting smoking.

7 0

3 years ago

If x has a continuous uniform distribution on the interval (0,5), what is the 25th percentile for x?

Natasha_Volkova [10]

Given that $X\sim\mathrm{Unif}(0,5)$ , it has PDF

$f_X(x)=\begin{cases}\dfrac15&\text{for }0\le x\l5\\\\0&\text{otherwise}\end{cases}$

and thus CDF

$F_X(x)=\mathbb P(X\le x)=\begin{cases}0&\text{for }x$

The 25th percentile is the value $X=k$ such that $\mathbb P(X\le k)=0.25$ . We have

$\mathbb P(X\le k)=\dfrac k5=0.25\implies k=1.25$

4 0

3 years ago