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djverab [1.8K]
4 years ago
10

What is the correct definition of pressure?

Physics
2 answers:
almond37 [142]4 years ago
8 0

Answer:

C. force per unit area

Explanation:

Pressure is defined to be the amount of force exerted per area.

P=F/A

This definition also means that the units of pressure are newtons per square meter

Levart [38]4 years ago
5 0

Answer:

C

Explanation:

because it's not a volume is mass

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A light bulb has a power rating of 60 W. What is the current running into it if it is plugged into a 120 V outlet?
kifflom [539]

Answer:

0.5 Amperes

Explanation:

Information that we have:

Power: P=60W

Voltage: V=120V

and we use the equation that relates this two quantities to the Current (I):

I=\frac{P}{V}

where I is the curent, P is the Power and V is the Voltage.

we substitute the values given for the Power and the Voltage to find the current:

I=\frac{60W}{120V}\\ I=0.5A

the Current running into the bulb is 0.5 Amperes

3 0
3 years ago
Moby lifted Tim off the ground a distance of 2 meters using a force of 2N. How much work did Moby do?
Damm [24]

Answer:

jdfjfkdidjdjdjdjdjdjddjdjdjdjdjdjdjjddj

3 0
3 years ago
If a small motor does 520 J of work to move a toy car 260 m, what force does the engine exert on the car?
ohaa [14]

Answer:

<h2>2 N</h2>

Explanation:

The force engine exert on the car can be found by using the formula

f =  \frac{w}{d}  \\

w is the workdone

d is the distance

From the question we have

f =  \frac{520}{260}  = 2 \\

We have the final answer as

<h3>2 N</h3>

Hope this helps you

4 0
3 years ago
Two loudspeakers are placed on a wall 3.00 m apart. A listener stands 3.00 m from the wall directly in front of one of the speak
Mashutka [201]

Answer:

Part a)

\Delta \phi = 2.2 \pi

Part b)

f = 411.3 Hz

Explanation:

As we know that the observer is standing in front of one speaker

So here the path difference of the two sound waves reaching to the observer is given as

\Delta x = 3\sqrt2 - 3

\Delta x = 1.24 m

now phase difference is related with path difference as

\Delta \phi = \frac{2\pi}{\lambda}(\Delta x)

\Delta \phi = \frac{2\pi}{\lambda}(1.24)

here in order to find the wavelength

\lambda = \frac{c}{f}

\lambda = \frac{340}{300} = 1.13

now we have

\Delta \phi = \frac{2\pi}{1.13}(1.24) = 2.2\pi

Part b)

Now we know that when phase difference is odd multiple of \pi

then in that case the the sound must be minimum

So nearest value for minimum intensity would be

\Delta \phi = 3\pi

so we have

3\pi = \frac{2\pi}{\lambda}(1.24)

so we have

\lambda = 0.827

now we have

\frac{340}{f} = 0.827

f = 411.3 Hz

4 0
3 years ago
g A rotating wheel requires 5.00 s to rotate 28.0 revolutions. Its angular velocity at the end of the 5.00-s interval is 96.0 ra
Setler [38]

Answer:

The angular acceleration of the wheel is 15.21 rad/s².

Explanation:

Given that,

Time = 5 sec

Final angular velocity = 96.0 rad/s

Angular displacement = 28.0 rev = 175.84 rad

Let \alpha be the angular acceleration

We need to calculate the angular acceleration

Using equation of motion

\theta=\omega_{i} t+\dfrac{1}{2}\alpha t^2

Put the value in the equation

175.84=\omega_{i}\times 5+\dfrac{1}{2}\times\alpha\times(5)^2

175.84=\omega_{i}\times 5+12.5\alpha......(I)

Again using equation of motion

\omega_{f}=\omega_{i}+\alpha t

Put the value in the equation

96.0=\omega_{i}+\alpha \times 5

On multiply by 5 in both sides

480=\omega_{i}\times 5+\alpha\times 25....(II)

On subtract equation (I) from equation (II)

480-175.84=\alpha(25-5)

304.16=\alpha\times20

\alpha=\dfrac{304.16}{20}

\alpha=15.21\ rad/s^2

Hence, The angular acceleration of the wheel is 15.21 rad/s².

5 0
3 years ago
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