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3 years ago

A crate falls from an airplane flying horizontally at an altitude of 2,000 m.

Physics

1 answer:

Hatshy [7]3 years ago

7 0

Answer:

20.2 seconds

Explanation:

The airplane (and therefore the crate) initially has no vertical velocity, so v₀ = 0 m/s.

The crate is in free fall, so a = -9.8 m/s².

The crate falls downward, so Δx = -2000 m.

Find: t, the time it takes for the crate to land.

Δx = v₀ t + ½ at²

-2000 m = (0 m/s) t + ½ (-9.8 m/s²) t²

t = 20.2 s

It takes 20.2 seconds for the crate to land.

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The neutron can be found in the nucleus of the atom with the proton.

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562

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3 years ago

A pickup truck is being driven down the highway carrying eight 100 gallon fish tank full of water. A hole is punctured in each t

irakobra [83]

Answer:

Explanation:

The velocity of the vehicle would increase because the the tanks (when filled with water) must have exerted a force which would reduce the velocity of the vehicle at a certain pressure on the gas pedal. Note that force equals mass multiplied by acceleration; as the mass decreases, so the force decreases. Thus, when the mass exerted by this tanks (on the vehicle) decrease as a result of the hole punctured in them, the force exerted by the tanks would also decrease causing an increase in velocity of the pick up truck when the same pressure is applied on the gas pedal throughout (before and after the puncture).

The conservation law that applied here is the law of conservation of energy which states that energy can neither be created nor destroyed but can be transformed from one form to another. This is because the energy the vehicle used in carrying the load (the tanks) was transformed to the energy that resulted in increasing it's velocity (no new energy was formed as the pressure on the gas pedal remained the same).

6 0

3 years ago

How many diffraction maxima are contained in a region of the Fraunhofer single-slit pattern, subtending an angle of 2.12°, for a

Luba_88 [7]

Answer:

Explanation:

We are given that

$\theta=2.12^{\circ}$

Slid width,a=0.110 mm= $0.11\times 10^{-3} m$

$1mm=10^{-3} m$

Wavelength, $\lambda=582 nm=582\times 10^{-9}$ m

$1nm=10^{-9} m$

We have to find the number of diffraction maxima are contained in a region of the Fraunhofer single-slit pattern.

$asin\theta=\frac{2N+1}{2}\lambda$

Using the formula

$0.11\times 10^{-3}sin(2.12)=\frac{2N+1}{2}(582\times 10^{-9})$

$2N+1=\frac{0.11\times 10^{-3}sin(2.12)\times 2}{582\times 10^{-9}}$

$2N+1=13.98$

$2N=13.98-1=12.98$

$N=\frac{12.98}{2}\approx 6$

Hence, 6 diffraction maxima are contained in a region of the Fraunhofer single-slit pattern

5 0

3 years ago

A soccer player heads the ball and sends it flying vertically upwards at a speed of 18.0 m/s . How high above the players ' head

Darya [45]

Answer:

<em>The ball travels up to 16.53 meters above the player's head</em>

Explanation:

<u>Vertical Launch Upwards</u>

In a vertical launch upwards, an object is launched vertically up from a height H without taking into consideration any kind of friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

$\displaystyle h_m=H+\frac{v_o^2}{2g}$

The initial speed of the soccer ball is vo=18 m/s. The initial height can be assumed to be zero because we are required to find the maximum height with respect to the player's head, where the vertical motion was initiated.

Calculate the maximum height:

$\displaystyle h_m=\frac{18^2}{2\cdot 9.8}$

$h_m=16.53\ m$

The ball travels up to 16.53 meters above the player's head

5 0

3 years ago