Answer:
Explanation:
Given that,
Mass of ball m = 2kg
Ball traveling a radius of r1= 1m.
Speed of ball is Vb = 2m/s
Attached cord pulled down at a speed of Vr = 0.5m/s
Final speed V = 4m/s
Let find the transverse component of the final speed using
V² = Vr²+ Vθ²
4² = 0.5² + Vθ²
Vθ² = 4²—0.5²
Vθ² = 15.75
Vθ =√15.75
Vθ = 3.97 m/s.
Using the conservation of angular momentum,
(HA)1 = (HA)2
Mb • Vb • r1 = Mb • Vθ • r2
Mb cancels out
Vb • r1 = Vθ • r2
2 × 1 = 3.97 × r2
r2 = 2/3.97
r2 = 0.504m
The distance r2 to the hole for the ball to reach a maximum speed of 4m/s is 0.504m
The required time,
Using equation of motion
V = ∆r/t
Then,
t = ∆r/Vr
t = (r1—r2) / Vr
t = (1—0.504) / 0.5
t = 0.496/0.5
t = 0.992 second
Answer:
Plz translate in english so that i can answer
Answer:
-0.4 m/s
Explanation:
According to the law of conservation of momentum, the total momentum of the bullet - rifle system must be conserved.
The total momentum before the shot is zero, since they are both at rest:
While the total momentum after the shot can be written as:
where
m = 10 g = 0.010 kg is the mass of the bullet
M = 5 kg is the mass of the rifle
v = 200 m/s is the velocity of the bullet
V is the recoil velocity of the rifle
Since the total momentum is conserved, we can write:
So
And solving for V, we find the recoil velocity:
and the negative sign indicates that the velocity is opposite to the bullet.
Answer:
All music in the world, is form only two notes and those notes are described below in detailed explanation.
Explanation:
In the chromatic scale, there are basically seven central musical notes, designated A, B, C, D, E, F, and G. They individual express a separate pitch or frequency. For illustration, the "central" A note has a pitch of 450 Hz, and the "common" B note has a pitch of 495 Hz.
Varieties Of Musical Notes You Require To Understand
Semibreve (Whole Note)
Minim (Half Note)
Crotchet (Quarter Note)
