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sdas [7]
3 years ago
12

A newly mated queen ant establishes a nest in an unoccupied patch of suitable habitat. Assuming that no disasters strike the nes

t, which type of equation is likely to best describe its population growth? (see book section: Population Growth Models)
logistic
quadratic
exponential
linear
circular
Biology
1 answer:
Alika [10]3 years ago
8 0

Answer:

Logistic

Explanation:

As the newly mated queen inhabit the new habitat, the population of the ants would increase slowly first followed by a rapid increase in the population size. Once the population size reaches the carrying capacity, it is leveled off.

Carrying capacity is the maximum number of the individuals of a population that can be supported indefinitely by a habitat. Once the population reaches the carrying capacity, one or other required resources become limited which in turn does not allow the exponential growth of the population.

This type of population growth wherein the exponential increase is followed by leveling out the population as the carrying capacity is reached, is called logistic population growth.

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Answer:

c. 1:2:1

The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.

Explanation:

If flower color were determined by a gene showing incomplete dominance, the possible genotypes and phenotypes are as follows:

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  • ww - white
  • Rw - pink

If pink sweet peas are self-pollinated, then a cross between two heterozygous individuals is done (Rw x Rw).

<u>From this cross the expected ratios are:</u>

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  • 1/4 ww (white)

So the null hypothesis is that the observed results exhibit a 1:2:1 ratio.

<h3><u>Chi square test</u></h3>

X^{2} = \sum \frac{(Observed - Expected)^2}{Expected}

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  • 40 White

Total 150

<u>The expected frequencies for our null hypothesis are:</u>

  • 1/4 x 150 = 37.5 Red
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X^{2} = \frac{(34- 37.5)^2}{37.5} + \frac{(76- 75)^2}{75} + \frac{(40- 37.5)^2}{37.5}

X^2=0.5067

The degrees of freedom (DF) are calculated as number of phenotypes - 1; in this case DF = 3-1 = 2.

If we look at the Chi square table, for 2 DF and a probability of p0.05, the critical value is 5.991

Our X^2 value of 0.5067 is less than the critical value, so we do not reject the null hypothesis. The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.

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Meristemic cells are simple but permanent cells are complex in nature.

Meristamic cell responsible for primary and secondary growth and permanent tissue helps in overall growth of plants

Explanation:

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