Answer:
allopolyploidy
Explanation:
Polyploidy is the condition by which a cell might have more than two chromosome sets that form homologous pairs. It might occur due to a failure or abnormality in cell division.
Autopolyploidy
Refer to a type of polyploidy in which an organism has more than two copies of homologous chromosomes. It results from the duplication of a group of chromosomes of the same species. Autopolyploid individuals have <u>at least three groups of homologous chromosomes</u>. Autopolyploidy is produced by the<u> gamete fusion of the same progenitor - same species</u>-, duplicating the number of chromosomes of diploid species. The autopolyploid cell has groups of homologous chromosomes. Autopolyploidy is produced mainly due to non-disjunction during meiosis.
Allopolyploidy
Refer to another type of polyploidy in which species have more than three sets of chromosomes in their cells. Allopolyploidy <u>occurs when two different species mate</u>, leading to the fusion of gametes that belong to different species and produce a new hybrid. The chromosomic complement has more than two copies of chromosomes. The hybrid is infertile with the parental species. The allopolyploid cells have chromosome groups that are not homologous.
In the exposed example two different species mate and produce a hybrid species.
I think the answer should be B as well hope it helps
The answer is B :)- because snow only falls below freezing.
Hmmm I’m not quite sure about that
Answer:
The chance of having a Child who is a Heterozygote is 50% , The chance of having a child that will completely come down with Alpers syndrome is 0%
Explanation:
Jack has a history of Alpers in his family
Jill has no history
lets assume Jack is a carrier : Ab ( because that is how he could have survived the first 10 lethal years )
Jill : AA
Therefore the probability/chance of Jack and Jill having a child with Alpers ( carrier ) syndrome will be 50 % as shown below
AA * Ab = AA , Ab, AA, Ab
The child produced by Jack and Jill will only be a carrier of the syndrome and not completely affected by the syndrome
