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Nataly [62]
3 years ago
12

PLEASE HELP, I NEED IT ASAP!!!

Mathematics
2 answers:
jonny [76]3 years ago
8 0
Try C. It’s the only decimal with one dot above it, that’s most likely the answer.
Igoryamba3 years ago
5 0

I am pretty sure it's A


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Given a long algebraic equation, what are some strategies that you can use to make simplifying and evaluating the equation more
krok68 [10]

Answer:

See explanation

Step-by-step explanation:

Given a long algebraic equation, the like terms can be collected. When you collect like terms, you reduce the length of the algebraic equation.

After that, you can factorize the equation where possible. When you factorize the equation. It becomes quite easier to solve it efficiently.

6 0
3 years ago
Can someone please show me how<br><br> 19169000*e^(0.15)= 222712201<br><br> When e= 2.7182818284?
Ierofanga [76]

Answer:

It doesn't. x = 22 271 201

Step-by-step explanation:

You are going to need a calculator no matter how you do it.

x =19 169 000 \times e^{0.15}

(a) The direct method

x = 19 169 000\times 2.718 281 828^{0.15} = 19 169 000 \times 1.161 834 243 = 22 271 201

(b) The indirect method

\ln \left (19 169 000\times 2.718 281 828^{0.15} \right ) = \ln(19 169 000) + 0.15 = 16.768 805 + 0.15 = 16.918 804\\\\e^{16.918 804} = 22 271 201

8 0
3 years ago
Factoring trinomials
Tcecarenko [31]

c^22c^2 + 13c +21 \\4c^2 + 13(2)c + 42\\(2c + 6)(2c+7)\\(c+3)(2c+7)


This is a way to factoring trinomials (there exist different equivalent methods).

Multiply the trinomial but the term accompanying  c^2. This is the second line. Then, you could take the square of the 4c^2, ant try to create a factor () () that will correspond to the expression in the second line. That is, we want 4c^2 + 13(2) c + 42 = (2c + ?) (2c + ?)

In ? we put the corresponding numbers that, if we multiply them we will obtain 42, and if we add them we will obtain 13. This numbers are 6 and 7. Then, we have (2c + 6) (2c +7)

The last step is divide by the number that we multipy in the first step.

4 0
3 years ago
A house was valued at $100,000 in the year 1987. The value appreciated to $165,000 by the year 2002.
iris [78.8K]

Answer:

  A) The annual multiplier was 1.0339; the annual increase was 0.0339 of the value.

  B) 3.39% per year

  C) $182,000

Step-by-step explanation:

A) Let's let t represent years since 1987. Then we can fill in the numbers and solve for r.

  165000 = 100000(1 +r)^15

  1.65^(1/15) = 1 +r . . . . . divide by 100,000; take the 15th root

  1.03394855265 -1 = r ≈ 0.0339

The value was multiplied by about 1.0339 each year.

__

B) The value increased by about 3.39% per year.

__

C) S = $100,000(1.03394855265)^18 ≈ $182,000

8 0
3 years ago
Need help asap<br> really need help
stich3 [128]

Answer:

(x,y)----(x,y+3)

Step-by-step explanation:

4 0
3 years ago
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