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3 years ago

The surface area of a cube is 2.535 m2.

1 answer:

5 0

Given:
Surface area of a cube = 2.535 m²

convert square meters to square centimeters:
1 square meter = 10,000 square centimeters

2.535 m² * 10,000 cm²/m² = 25,350 cm²

B.The number representing the surface area would increase.
(from 2.535 to 25,350)

E.The actual surface area would stay the same.
(only the units used differ).

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Label based on TRIANGLE INEQUALITY. 12 X Х 8

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Step-by-step explanation:

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2 years ago

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3 years ago

5x + 9 = 10x - 9 How do I solve this?

dangina [55]

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3 years ago

Read 2 more answers

Let the number of chocolate chips in a certain type of cookie have a Poisson distribution. We want the probability that a cookie

ludmilkaskok [199]

Answer:

$\lambda \geq 6.63835$

Step-by-step explanation:

The Poisson Distribution is "a discrete probability distribution that expresses the probability of a given number of events occurring in a fixed interval of time or space if these events occur with a known constant mean rate and independently of the time since the last event".

Let X the random variable that represent the number of chocolate chips in a certain type of cookie. We know that $X \sim Poisson(\lambda)$

The probability mass function for the random variable is given by:

$f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...$

And f(x)=0 for other case.

For this distribution the expected value is the same parameter $\lambda$

$E(X)=\mu =\lambda$

On this case we are interested on the probability of having at least two chocolate chips, and using the complement rule we have this:

$P(X\geq 2)=1-P(X$

Using the pmf we can find the individual probabilities like this:

$P(X=0)=\frac{e^{-\lambda} \lambda^0}{0!}=e^{-\lambda}$

$P(X=1)=\frac{e^{-\lambda} \lambda^1}{1!}=\lambda e^{-\lambda}$

And replacing we have this:

$P(X\geq 2)=1-[P(X=0)+P(X=1)]=1-[e^{-\lambda} +\lambda e^{-\lambda}[]$

$P(X\geq 2)=1-e^{-\lambda}(1+\lambda)$

And we want this probability that at least of 99%, so we can set upt the following inequality:

$P(X\geq 2)=1-e^{-\lambda}(1+\lambda)\geq 0.99$

And now we can solve for $\lambda$

$0.01 \geq e^{-\lambda}(1+\lambda)$

Applying natural log on both sides we have:

$ln(0.01) \geq ln(e^{-\lambda}+ln(1+\lambda)$

$ln(0.01) \geq -\lambda+ln(1+\lambda)$

$\lambda-ln(1+\lambda)+ln(0.01) \geq 0$

Thats a no linear equation but if we use a numerical method like the Newthon raphson Method or the Jacobi method we find a good point of estimate for the solution.

Using the Newthon Raphson method, we apply this formula:

$x_{n+1}=x_n -\frac{f(x_n)}{f'(x_n)}$

Where :

$f(x_n)=\lambda -ln(1+\lambda)+ln(0.01)$

$f'(x_n)=1-\frac{1}{1+\lambda}$

Iterating as shown on the figure attached we find a final solution given by:

$\lambda \geq 6.63835$

4 0

3 years ago

Based on the diagram, which expresses all possible

qaws [65]

The expression that expresses all possible lengths of segment AB is 27 < AB < 81. The correct option is the second option 27 < AB < 81

<h3>Properties of a triangle</h3>

From the question, we are to determine the expression that expresses all possible lengths of segment AB

From one of the properties of a triangle,

The third side of any triangle is greater than the difference of the other two sides; and the third side of any triangle is lesser than the sum of the two other sides

Then, we can write that

AB < 27 + 54

and

AB > 54 - 27

Putting the two inequalities together, we get

54 - 27 < AB < 27 + 54

27 < AB < 81

Hence, the expression that expresses all possible lengths of segment AB is 27 < AB < 81. The correct option is the second option 27 < AB < 81

Learn more on the Properties of a triangle here: brainly.com/question/1851668

#SPJ1

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1 year ago