3 years ago

A dice is rolled 4 times. What is the probability of showing a 6 on every roll?

1 answer:

Oliga [24]3 years ago

3 0

Answer:

1/6

Step-by-step explanation:

If the dice is rolled 4 times than the probability you will roll a 6 is 1/6 since there are only six numbers

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zavuch27 [327]

To find the measurement of PS, you would add the lengths of PQ and PS. 18.4+4.7=23.1. The answer is 23.1 cm

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sammy [17]

It 54 thank you welcome you

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sertanlavr [38]

Given:

Consider the given expression is

$(4x^3y^2)^{\frac{3}{10}}$

To find:

The radical form of given expression.

Solution:

We have,

$(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

Therefore, the required radical form is $\sqrt[5]{8y^3}\sqrt[10]{x^9}$ .

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Citrus2011 [14]

Answer:c

Step-by-step explanation:just did the test

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lozanna [386]

I think its the same on both sides so it would be 154 hope this helps and is right have a nice day

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