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Arisa [49]
3 years ago
10

Maddy mows acres in 2 hours how many acres does maddy mw per hour

Mathematics
1 answer:
photoshop1234 [79]3 years ago
8 0
She mows 1/2 an acre per hour
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5. In the figure, . Solve for . Show your work.
natima [27]

Answer:

15

Step-by-step explanation:

6/10=9/x

cross multiply

6x=9*10

6x=90

x=90/6x=15

3 0
3 years ago
Solve the equation tanxtan(x – 45°)=0 for 0° < x < 360°.
Lady_Fox [76]

Answer:

\tan \left(\frac{\sin \left(x\right)-\cos \left(x\right)}{\cos \left(x\right)+\sin \left(x\right)}\right)

Step-by-step explanation:

4 0
3 years ago
I need help with this question
malfutka [58]

Answer:


Step-by-step explanation:


7 0
3 years ago
Please help with these math questions part 2
NikAS [45]
5).
and
6).
The volume of a sphere is

               (4/3) (pi) (radius)³ .

In #5, the 'pi' is already there next to the answer window.
You just have to come up with the (4/3)(radius³).

Remember that the radius = 1/2 of the diameter.

7).  The volume of a cylinder is

                         (pi) (radius²) (height) .

Divide the juice in the container by the volume of one can,
to get the number of cans he can fill.

8).  The volume of a cone is

                     (1/3) (pi) (radius of the round bottom)² (height) .

He starts with a small cone, he then adds clay to it to make it higher.
The question is:  How much clay does he ADD to the short one,
to make the bigger one ?

Use the formula to find the volume of the short one.
Use the formula again to find the volume of the bigger one.
Then SUBTRACT the smaller volume from the bigger volume.
THAT's how much clay he has to ADD.

Notice that the new built-up cone has the same radius
but more height than the first cone.
_______________________________________

Don't worry if you don't understand this.

The answer will be this number:

 (1/3) (pi) (radius²) (height of the big one minus height of the small one).
6 0
3 years ago
Let c be parametrized by x = et sin (10t) and y = et cos (10t) for 0 ≤ t ≤ 2. find the length l of
marysya [2.9K]
C:x(t)=e^t\sin10t;\,y(t)=e^t\cos10t;\,0\le t\le2

\displaystyle\int_0^2\sqrt{x'(t)^2+y'(t)^2}\,\mathrm dt
\displaystyle=\int_0^2\sqrt{(e^t\sin10t+10e^t\cos10t)^2+(e^t\cos10t-10e^t\sin10t)^2}\,\mathrm dt
\displaystyle=\int_0^2e^t\sqrt{\sin^210t+20\sin10t\cos10t+100\cos^210t+\cos^210t-20\sin10t\cos10t+100\sin^210t}\,\mathrm dt
=\displaystyle\int_0^2e^t\sqrt{1+100}\,\mathrm dt
=\displaystyle\sqrt{101}(e^2-1)
7 0
3 years ago
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