The correct option is C. The amount of MgCl2. we know this because <span>no matter how much you increase KOH, if you dont increase Mgcl2, the amount of Mg(OH)2 remains the same. Hope this works for you</span>
Elements can either lose or gain an electron(s) to attain an octet configuration and form ions.
Metals lose an electron(s) to attain a stable configuration and form positively charged ions called cations.
Non-metals, on the other hand, gain an electron(s) to attain an octet configuration and form negatively charged ions known as anions.
In this case, Vanadium is a transitional element with 5 valence electrons.
Like other transition elements, vanadium may have multiple oxidation numbers.
Vanadium has an atomic number of 23 and a configuration of [Ar] 3d³4s², therefore, vanadium ion (V²⁺) formed by loss of two electrons will have a configuration of [Ar] 3d³
