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faltersainse [42]
3 years ago
5

Which kind of nuclear decay does not alter the identity of the atom?

Chemistry
2 answers:
PtichkaEL [24]3 years ago
5 0
For alpha and beta decay it does because the proton number changes.
During gamma, there is no change of identity, just energy
Debora [2.8K]3 years ago
3 0

Answer: gamma decay

Explanation:

1. Alpha decay: In this process, alpha particles is emitted when a heavier nuclei decays into lighter nuclei. The alpha particle released has a charge of +2 units.

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}+_2^4\alpha  

2. Beta-decay: In this process, a neutron gets converted into a proton and an electron releasing a beta-particle. The beta particle released carries a charge of -1 units.

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

3. Gamma decay: in this process, an unstable nuclei gives off excess energy by a spontaneous electromagnetic process and releases \gamma -radiations. These radiations does not carry any charge and are electrically neutral and thus the identity of the atom undergoing gamma decay do not change.

_Z^A\textrm{X}^*\rightarrow _Z^A\textrm{X}+_0^0\gamma

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If the pH of a 1.00-in. rainfall over 1800 miles2 is 3.70, how many kilograms of sulfuric acid, H2SO4, are present, assuming tha
NARA [144]
There are 2.32 x 10^6 kg sulfuric acid in the rainfall. 

Solution: 
We can find the volume of the solution by the product of 1.00 in and 1800 miles2: 
     1800 miles2 * 2.59e+6 sq m / 1 sq mi = 4.662 x 10^9 sq m 
     1.00 in * 1 m / 39.3701 in = 0.0254 m  
     Volume = 4.662 x 10^9 m^2 * 0.0254 m
                  = 1.184 x 10^8 m^3 * 1000 L / 1 m3
                  = 1.184 x 10^11 Liters 

We get the molarity of H2SO4 from the concentration of [H+] given by pH = 3.70: 
     [H+] = 10^-pH = 10^-3.7 = 0.000200 M 
     [H2SO4] = 0.000100 M  
 
By multiplying the molarity of sulfuric acid by the volume of the solution, we can get the number of moles of sulfuric acid: 
     1.184 x 10^11 L * 0.000100 mol/L H2SO4 = 2.36 x 10^7 moles H2SO4 

We can now calculate for the mass of sulfuric acid in the rainfall: 
     mass of H2SO4 = 2.36 x 10^7 moles * 98.079 g/mol
                               = 2.32 x 10^9 g * 1 kg / 1000 g
                               = 2.32 x 10^6 kg H2SO4
3 0
3 years ago
Read 2 more answers
Calculate the volume of 11 g of CO2 at NTP ?​
Kitty [74]
<h3>Answer:</h3>

5.6 Liters

<h3>Explanation:</h3>
  • N.T.P. refers to the standard temperature and pressure (S.T.P).

We need to know that;

  • One mole of a gas occupies a volume of 22.4 liters at N.T.P.

In this case;

We have 11 g of CO₂

But, 1 mole of CO₂ occupies 22.4 l at N.T.P.

1 mole of CO₂ = 44 g

Therefore;

44 g of CO₂ = 22.4 liters

What about 11 g ?

= (11 g × 22.4 l)÷ 44 g

= 5.6 l

Therefore, 11 g of CO₂ will occupy a volume of 5.6 liters at N.T.P.

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3 years ago
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Cerrena [4.2K]

Answer:

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2 years ago
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olchik [2.2K]

Answer:

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