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faltersainse [42]
3 years ago
5

Which kind of nuclear decay does not alter the identity of the atom?

Chemistry
2 answers:
PtichkaEL [24]3 years ago
5 0
For alpha and beta decay it does because the proton number changes.
During gamma, there is no change of identity, just energy
Debora [2.8K]3 years ago
3 0

Answer: gamma decay

Explanation:

1. Alpha decay: In this process, alpha particles is emitted when a heavier nuclei decays into lighter nuclei. The alpha particle released has a charge of +2 units.

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}+_2^4\alpha  

2. Beta-decay: In this process, a neutron gets converted into a proton and an electron releasing a beta-particle. The beta particle released carries a charge of -1 units.

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

3. Gamma decay: in this process, an unstable nuclei gives off excess energy by a spontaneous electromagnetic process and releases \gamma -radiations. These radiations does not carry any charge and are electrically neutral and thus the identity of the atom undergoing gamma decay do not change.

_Z^A\textrm{X}^*\rightarrow _Z^A\textrm{X}+_0^0\gamma

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Electronic and electrical devices differ in the way they use _____.
Katena32 [7]
Election current because voltage is a measurement, information doesn't apply to all electrical devices and the wires within are usually copper bc it conducts and hardly ever will the wires be anything different because copper is cheap
3 0
2 years ago
Based on the shapes of the water drops in part D, how does the attractive force between water and wax compare to the attractive
Minchanka [31]

Answer:

Because the cohesive forces inside the droplets are stronger than the adhesive forces between both the drops and the wax, water does not penetrate waxed surfaces. Because the adhesive forces between the liquid and the glass are stronger than the cohesive forces inside the water, water wets glass and spreads out across it.

Explanation:

EDMENTUM

4 0
1 year ago
S(s)+3F2(g)->SF6(g) how many mol of F2 are required to react completely with 2.30 mol of S?
Brilliant_brown [7]

Answer:  There are 6.9 mol of F_{2} are required to react completely with 2.30 mol of S.

Explanation:

The given reaction equation is as follows.

S(s) + 3F_{2}(g) \rightarrow SF_{6}(g)

Here, 1 mole of S is reaction with 3 moles of F_{2} which means 1 mole of S requires 3 moles of F_{2}.

Therefore, moles of F_{2} required to react completely with 2.30 moles S are calculated as follows.

1 mol S = 3 mol F_{2}\\2.30 mol S = 3 mol F_{2} \times 2.30 \\= 6.9 mol F_{2}

Thus, we can conclude that there are 6.9 mol of F_{2} are required to react completely with 2.30 mol of S.

3 0
3 years ago
Determine the formula weight of caffeine, C₈H₁₀N₄O₂. Provide an answer to two decimal places.
arlik [135]

Let's find

\\ \tt\hookrightarrow C_8H_10N_4O_2

  • We need accurate mass

\\ \tt\hookrightarrow 8(12.011)+10(1.007)+4(14.006)+2(16.0)

\\ \tt\hookrightarrow 96.088+10.07+56.024+32.0

\\ \tt\hookrightarrow 196.182g/mol

\\ \tt\hookrightarrow 196.18g/mol\:or 196.18u

5 0
2 years ago
Read 2 more answers
calculate the concentration of silver in a 100.0 mL solution of silver bromide at 25oC (298 K) when the Ksp is 5.0 x 10-13
Sliva [168]

Answer:

Concentration AgBr at saturation = 7.07 x 10⁻⁷M

Explanation:

Given AgBr(s) => Ag⁺(aq) + Br⁻(aq) ; Ksp = 5 x 10⁻¹³ = [Ag⁺][Br⁻]

    I       ---                0              0

    C     ---               +x             +x

     E     ---                 x               x

[Ag⁺][Br⁻] = (x)(x) = x² = 5 x 10⁻¹³ => x = SqrRt(5 x 10⁻¹³) = 7.07 x 10⁻⁷M

4 0
2 years ago
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