Answer:
Hexaflourine Pentaiodide?
Explanation:
f = flourine (6 = hexa)
i = iodine (5 = penta) + ide
Well, its a very simple process actually. Here is how it works;
When molecular hydrogen, also known as H2, and oxygen, also known as O2, are combined and are able to react together, energy is released and the molecules of the hydrogen and the oxygen. These can combine to form either water or hydrogen peroxide, depending on how the chemicals mix.
I hope I made your day a little easier,
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Hello!
We have the following data:
ps: we apply Ka in benzoic acid to the solution.
[acid] = 0.235 M (mol/L)
[salt] = 0.130 M (mol/L)
pKa (acetic acid buffer) =?
pH of a buffer =?
Let us first find pKa of benzoic acid, knowing that Ka (benzoic acid) = 
So:





Now, using the abovementioned data for the pH formula of a buffer solution or (Henderson-Hasselbalch equation), we have:
![pH = pKa + log\:\dfrac{[salt]}{[acid]}](https://tex.z-dn.net/?f=%20%20pH%20%3D%20pKa%20%2B%20log%5C%3A%5Cdfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D%20%20%20)





Note:. The pH <7, then we have an acidic solution.
I Hope this helps, greetings ... DexteR! =)
Answer:
0.07789 M is the sodium hydroxide concentration.
Explanation:
Mass of potassium hydrogen phthalate = 0.6986 g
Molar mass of potassium hydrogen phthalate = 204.22 g/mol
Moles of potassium hydrogen phthalate = 

According to reaction , 1 mole og KHp reactswith 1 mole of NaOH , then 0.003421 moles of KHp will react with :

Moles of NaOH = 0.003421 mole
Volume of NaOH solution = 43.92 ml = 0.04392 L ( 1 mL = 0.001L)

Concentration of NaOH :

0.07789 M is the sodium hydroxide concentration.