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Yanka [14]
3 years ago
8

A doctor's Order is 0.125 g of ampicillin. The liquid suspension on hand contains 250 mg/s. How many milliliters (mL) of the sus

pension are required? a) 0.0025 mL b) 3.0 mL c) 2.5 mL d) 6.1mL e) 0.0061mL
Chemistry
1 answer:
Molodets [167]3 years ago
7 0

Answer:

c) 2.5 mL

Explanation:

Solution

Doctors order = 0.125g

and

The liquid suspension concentration = 250 mg/5ml

= 0.250g/5ml

Or 0.05g/ml

Amount of ml of suspension required = 0.125g/(0.05g/ml) = 2.5ml

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Taking into account the reaction stoichiometry, 0.886 grams of O₂ can be prepared by the decomposition of 12 grams of mercury oxide.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction of the decomposition of mercury oxide is:

2 HgO  → 2 Hg + O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • HgO: 2 moles  
  • Hg: 2 moles
  • O₂: 1 mole

The molar mass of the compounds is:

  • HgO: 216.59 g/mole
  • Hg: 200.59 g/mole
  • O₂: 32 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

HgO: 2 moles ×216.59 g/mole= 433.18 grams

Hg: 2 moles ×200.59 g/mole= 401.18 grams

O₂: 1 mole ×32 g/mole= 32 grams

<h3>Mass of oxygen formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 433.18 grams of HgO form 32 grams of O₂, 12 grams of HgO form how much mass of O₂?

mass of O_{2} =\frac{12 grams of HgOx 32 grams of O_{2}}{433.18 grams of HgO}

<u><em>mass of O₂= 0.886 grams</em></u>

Then, 0.886 grams of O₂ can be prepared by the decomposition of 12 grams of mercury oxide.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

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