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Answer:
Cr
Explanation:
Cr goes from +3 to +6 and when it increases it means is being oxidized.
<h3><u>Answer;</u></h3>
The temperatures of the two substances equalize.
<h3><u>Explanation;</u></h3>
- When two objects at different temperatures are placed in contact, heat flows from the warmer object to the cooler one until the temperature of both objects is the same.
- <em><u>The amount of heat that flows from a warmer object is the same as the amount of heat that flows into a cooler object. Because the direction of heat flow is opposite for the two objects, the sign of the heat flow values must be opposite. </u></em>
- <em><u>In line with the law of conservation of energy, the amount of heat lost by a warmer object equals the amount of heat gained by a cooler object. Therefore the amount of heat lost by carbon dioxide is equal to the amount of heat gained by water.</u></em>
Metals are good conductors of heat and electricity
Metals are good conductors due to presence of free electrons
They act as carrier to conduct heat or electricity.
So
Aluminum spoon will heat up as it is of metal
Iron spoon will heat up as it is of metal
Silver spoon will also heat up as it is of metal
Wood is a bad conductor of heat. It is an insulator
Wood has air space or pockets in its structure which makes it a bad conductor (it cannot conduct heat)
So a wooden spoon will be stay coolest as it is an insulator
Answer:
The given statement is true.
Explanation:
Initially, the addition of borane to the alkene takes place in the form of a concerted reaction owing to the dissociation of the bond and subsequent formation, which occurs at a similar time. After that the Anti Markovnikov supplementation of boron takes place. The addition of this atom takes place with the less substituted carbon of the alkene that then substitutes the molecule of hydrogen on the more substituted carbon.
Then through the donation of a pair of electrons from the hydrogen peroxide ion, the process of oxidation takes place resulting in the formation of trialkylborane. After this realignment of an R group with its pair of bonding, electrons take place with adjacent oxygen resulting in the withdrawal of a hydroxide ion. Eventually, the trialkylborate reacts with the aqueous NaOH to generate alcohol and sodium borate as the side product.