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Natalija [7]
3 years ago
15

The function f has first derivative given by f'(x)=(x)^1/2/1+x+x^3. What is the x-coordinate of the inflection point of the grap

h of f?
a. 1.008
b. 0.473
c. 0
d. -0.278
e. the graph has no inflection points
Mathematics
1 answer:
Anestetic [448]3 years ago
4 0
Inflection at f'(x) = 0 
<span>
x^1/2 / (1 + x + x^3) = 0 </span>

<span>The x coordinate is x = 0 </span>
<span>
or "C" from your choices there. </span>

<span>The simplest way is to notice that this happens when x = 0. The reason is you got: </span>
<span>
x^1/2 / (some expression) </span>
<span>
at x = 0 the numerator is 0 so unless the denominator is also 0 the result is 0. </span>
<span>
The denominator for x = 0 is 1 so you get </span>
<span>
0/1 = 0.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
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