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Mumz [18]
3 years ago
5

A company has to buy computers and printers. Each computer, x, costs $550 and each printer, y, costs $350. If the company spends

$8,800 and buys a total of 20 machines, how many of each did it buy?
Enter a system of equations to represent the situation, then solve the system.

Mathematics
1 answer:
poizon [28]3 years ago
7 0

Answer:

The company bought 9 computers and 11 printers.

Step-by-step explanation:

Given that a company has to buy computers and printers, and each computer, x, costs $ 550 and each printer, y, costs $ 350, if the company spends $ 8,800 and buys a total of 20 machines, to determine how many of each did it buy the following calculation must be performed:

20 x 550 + 0 x 350 = 11,000

15 x 550 + 5 x 350 = 10,000

10 x 550 + 10 x 350 = 9,000

9 x 559 + 11 x 350 = 8,800

Thus, the company bought 9 computers and 11 printers.

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Answer:

0.0579 is the probability that mean systolic blood pressure is between 119 and 122 mm Hg for the sample.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 114.8 mm Hg

Standard Deviation, σ = 13.1 mm Hg

Sample size = 23

We are given that the distribution of systolic blood pressures is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling:

\displaystyle\frac{\sigma}{\sqrt{n}} = \frac{13.1}{\sqrt{23}} = 2.731

P(blood pressure is between 119 and 122 mm Hg)

P(119 \leq x \leq 122) = P(\displaystyle\frac{119 - 114.8}{2.731} \leq z \leq \displaystyle\frac{122-114.8}{2.731}) = P(1.537 \leq z \leq 2.636)\\\\= P(z \leq 2.636) - P(z < 1.537)\\= 0.9958 - 0.9379 = 0.0579= 5.79\%

P(119 \leq x \leq 122) = 5.79\%

0.0579 is the probability that mean systolic blood pressure is between 119 and 122 mm Hg for the sample.

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