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3 years ago

Could someone help please

Mathematics

2 answers:

posledela3 years ago

6 0

78+12 = 90 positive test

not pregnant given positive test 12

12/90

.13

Taya2010 [7]3 years ago

4 0

The answer would be b probably

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Kim asked the first 50 kids to school in the morning how they feel about waking up early. she uses their response to predict the

True [87]

Kim's method of sampling the students in the given scenario is said to; It is not a random survey.

<h3>What is a random sample?</h3>

Random sampling is defined as a sampling technique whereby each sample has an equal probability of being chosen. This means that a sample chosen randomly is meant to be an unbiased representation of the total population.

In this question, we are told that Kim asked the first 50 kids to school in the morning about a question and used their responses to arrive at a conclusion.

Now, Kim's method is not random because it is biased as only those who came earliest were asked.

Read more about Random Survey at;brainly.com/question/251701

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4 0

2 years ago

Peter planted 5/12 of his garden with asparagus and 3/12 with beans.

UkoKoshka [18]

Answer: He has planted 2/3 and there is 1/3 left to plant.

Explanation: You need to add your fractions together, because each of those is a section of the garden and you need the total of how much of the garden he has planted.

This isn’t too difficult because the denominators are the same.

5/12 + 3/12 = 8/12

It is 8/12 because since the denominators are the same, you just need to add the numerators. Imagine you have a pie that’s cut into 12 pieces, and you and your friends take 5, and then your family takes 3. How many or gone now? 8 pieces. From how many pieces? 12 pieces. So 8/12 pieces are gone.

So Peter has planted 8/12 of his garden. This however, can be simplified, because both of those numbers divide by 4.

8/4 = 2
12/4 = 3

So 8 is now 2, and 12 is now 3.

This is now 2/3.

If there is 2/3 gone, you need to figure out how much is left to get you to 1.

In this instance, 1 can be rewritten as 3/3, because 3 divided by 3 is 1.

In order to get from 2/3 to 1, you need to add 1/3, one more third to the two thirds you already have.

This means Peter has 1/3 left to plant.

Hope this helps :)

7 0

3 years ago

Which statements are true? Check all that apply. TIMED! WILL GIVE BRAINLIEST!

gladu [14]

Answer:

The 1st, 3rd, 4th, 5th are correct

7 0

3 years ago

Solve for x using the given diagram

blagie [28]

Answer:

Step-by-step explanation:

Look a t the picture.

The triangles on the picture are similar.

Therefore the sides are in proportion:

$\dfrac{8x}{10}=\dfrac{4}{5x}$ <em>cross multiply</em>

$(8x)(5x)=(4)(10)$

$40x^2=40$ <em>divide both sides by 40</em>

$x^2=1\to x=\sqrt1\\\\x=1$

7 0

3 years ago

What is Limit of StartFraction StartRoot x + 1 EndRoot minus 2 Over x minus 3 EndFraction as x approaches 3?

scoray [572]

Answer:

<u /> $\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \boxed{ \frac{1}{4} }$

General Formulas and Concepts:

<u>Calculus</u>

Limits

Limit Rule [Variable Direct Substitution]:
$\displaystyle \lim_{x \to c} x = c$

Special Limit Rule [L’Hopital’s Rule]:
$\displaystyle \lim_{x \to c} \frac{f(x)}{g(x)} = \lim_{x \to c} \frac{f'(x)}{g'(x)}$

Differentiation

Derivatives
Derivative Notation

Derivative Property [Addition/Subtraction]:
$\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$
Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:
$\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given limit</em>.

$\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3}$

<u>Step 2: Find Limit</u>

Let's start out by <em>directly</em> evaluating the limit:

[Limit] Apply Limit Rule [Variable Direct Substitution]:
$\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \frac{\sqrt{3 + 1} - 2}{3 - 3}$
Evaluate:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \frac{\sqrt{3 + 1} - 2}{3 - 3} \\& = \frac{0}{0} \leftarrow \\\end{aligned}$

When we do evaluate the limit directly, we end up with an indeterminant form. We can now use L' Hopital's Rule to simply the limit:

[Limit] Apply Limit Rule [L' Hopital's Rule]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\\end{aligned}$
[Limit] Differentiate [Derivative Rules and Properties]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \leftarrow \\\end{aligned}$
[Limit] Apply Limit Rule [Variable Direct Substitution]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \\& = \frac{1}{2\sqrt{3 + 1}} \leftarrow \\\end{aligned}$
Evaluate:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \\& = \frac{1}{2\sqrt{3 + 1}} \\& = \boxed{ \frac{1}{4} } \\\end{aligned}$

∴ we have <em>evaluated</em> the given limit.

___

Learn more about limits: brainly.com/question/27807253

Learn more about Calculus: brainly.com/question/27805589

___

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

3 0

2 years ago