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Genrish500 [490]

2 years ago

7

A number cube is rolled 35 times and the results are recorded in the table.A goodness-of-fit chi-square test is to be used to te

st the null hypothesis that the cube is fair. At a significance level of α = 0.05, what is the value of chi-square and the appropriate conclusion?

1 answer:

denpristay [2]2 years ago

7 0

Answer:

Where's the table we can go off of??

Step-by-step explanation:

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A new car is purchased for 19000 dollars. The value of the car depreciates at 11.25% per year. What will the value of the car be

ioda

Answer: The answer is 3573.64

Step-by-step explanation:

Exponential Functions:

y=ab^x

a=starting value = 19000

r=rate = 11.25%=0.1125

Exponential Decay:

b=1-r=1-0.1125=0.8875

Write Exponential Function:

y=19000(0.8875)^x

Plug in time for x:

y=19000(0.8875)^14

y= 3573.6388855

Evaluate :

y≈3573.64

5 0

3 years ago

Olivia has a certain number of pieces of candy that she wants to share evenly with her siblings. She has 2 sisters and a brother

Svetlanka [38]

Probally not sorry hhaahhaa

3 0

2 years ago

Read 2 more answers

Find the equation of the regression line and the value of the correlation coefficient (r).

tino4ka555 [31]

Answer:

According with the graph:

1.) The equation of the regresion line is: y=5,720.10391 x + 957.225810

2.) The values of the correlation coefficient is 0.86

Step-by-step explanation:

In the graph is shown:

1.) Line of Best Fit

y=5720.10391 x + 957.225810

2.) Correlation

.86

3 0

2 years ago

Penny's function has an output that is four more than three times the input. Johns function expressed in slope-intercept form is

jonny [76]

John's function : y = 3.5x - 4
Penny's function : y = 3x + 4

C. John's function has a greater rate of change, because 3.5 > 3

5 0

3 years ago

The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop

Anettt [7]

Answer:

a. $\frac{1}{15}$

b. $\frac{2}{5}$

c. $\frac{14}{15}$

d. $\frac{8}{15}$

Step-by-step explanation:

Given that there are two laptop machines and four desktop machines.

On a day, 2 computers to be set up.

To find:

a. probability that both selected setups are for laptop computers?

b. probability that both selected setups are desktop machines?

c. probability that at least one selected setup is for a desktop computer?

d. probability that at least one computer of each type is chosen for setup?

Solution:

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

a. Favorable cases for Both the laptops to be selected = $_2C_2$ = 1

Total number of cases = 15

Required probability is $\frac{1}{15}$ .

b. Favorable cases for both the desktop machines selected = $_4C_2=6$

Total number of cases = 15

Required probability is $\frac{6}{15} = \frac{2}{5}$ .

c. At least one desktop:

Two cases:

1. 1 desktop and 1 laptop:

Favorable cases = $_2C_1\times _4C_1 = 8$

2. Both desktop:

Favorable cases = $_4C_2=6$

Total number of favorable cases = 8 + 6 = 14

Required probability is $\frac{14}{15}$ .

d. 1 desktop and 1 laptop:

Favorable cases = $_2C_1\times _4C_1 = 8$

Total number of cases = 15

Required probability is $\frac{8}{15}$ .

8 0

3 years ago