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3 years ago

Describe how the current in a circuit changes if the resistance increases and the voltage remains constant

1 answer:

3 0

Current = (voltage) / (Resistance)

From the equation, with 'resistance' in the denominator,
we can see that if the resistance increases and the voltage
doesn't change, the current should decrease.

Laboratory experiments confirm this perfectly.

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Materials in which electric charges move freely such as copper and aluminum are called

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Answer:

Conductors allow electric charges to move freely

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4 years ago

Using the words mass and distance explain why astronauts experience less gravitational pull than on Earth?

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Answer:the amount of distance you go up the less mass you'll have witch mean less gravity for your body

Explanation:

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A seventh grade class is studying the solar system. A small group of students wanted to expand their studies to include the form

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3 years ago

Read 2 more answers

A current flowing through you of more than 5 ma is considered dangerous. Why do we see warnings about high voltage, rather than

svet-max [94.6K]

Answer:

V = 500 volts

I = 50 nA

Explanation:

We usually see 'high voltage' sign rather than 'high current' this is due to the fact that the amount of current depends upon the resistance of the body,

The relation of voltage, current and resistance is given by Ohm's law,

V = IR

I = V/R

As you can see, current and resistance are inversely related, the lower the resistance of the body, the higher will be the current flowing through the body.

What voltages are dangerous even if the skin is dry?

A dry human body has a resistance of approximately 100 kΩ and it gets reduced if the body is wet.

For a current of 5 mA, the corresponding voltage is,

V = 0.005*100,000

V = 500 volts

Therefore, for a dry human body, a voltage of 500 volts would be dangerous.

If voltage differences that are observed are about 0.5 mV, and the resistance of the skin is about 10 kΩ, what size currents are involved?

I = V/R

I = 0.0005/10,000

I = 50×10⁻⁹ A

I = 50 nA

Therefore, a current of 50 nA would be flowing through the EEG.

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3 years ago

An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 2.00 mm. If a

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Answer:

a. 11.5kv/m

b.102nC/m^2

c.3.363pF

d. 77.3pC

Explanation:

Data given

$area=7.60cm^{2}\\ distance,d=2mm\\voltage,v=23v$

to calculate the electric field, we use the equation below

V=Ed

where v=voltage, d= distance and E=electric field.

Hence we have

$E=v/d\\E=\frac{23}{2*10^{-3}} \\E=11.5*10^{3} v/m\\E=11.5Kv/m$

b.the expression for the charge density is expressed as

σ=ξE

where ξ is the permitivity of air with a value of 8.85*10^-12C^2/N.m^2

If we insert the values we have

$8.85*10^{-12} *11500\\1.02*10^{-7}C/m^{2} \\102nC/m^{2}$

from the expression for the capacitance

$C=eA/d$

if we substitute values we arrive at

$C=\frac{8.85*10^{-12}*7.6*10^{-4}}{2*10^{-3} } \\C=\frac{6.726*10^{-15} }{2*10^{-3} } \\C=3.363*10^{-12}F\\C=3.363pF$

d. To calculate the charge on each plate, we use the formula below

$Q=CV\\Q=23*3.363*10^{-12}\\ Q=7.73*10^{-12}\\ Q=77.3pC$

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4 years ago