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irakobra [83]
3 years ago
6

What happens to the power when the voltage doubles?

Physics
1 answer:
posledela3 years ago
3 0

Answer:

Option D. It quadruples

Explanation:

Let the initial voltage be V.

Let the initial power be P.

We shall determine the final power of the circuit as follow:

Initial voltage (V₁) = V

Initial power (P₁) = P

Final voltage (V₂) = double the initial voltage = 2P

Final power (P₂) =?

NOTE: Resistor (R) is constant

P = V² / R

Cross multiply

PR = V²

Divide both side by P

R = V² / P

Thus

V²₁ / P₁ = V²₂ / P₂

V² / P = (2V)² / P₂

V² / P = 4V² / P₂

Cross multiply

V² × P₂ = P × 4V²

Divide both side by V²

P₂ = P × 4V² / V²

P₂ = P × 4

P₂ = 4P

Thus, the power will be four times the initial power i.e quadruple.

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Explanation:

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4 0
4 years ago
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What would be the weight of the moon if it were resting on the surface of the earth
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We need to be careful here.
The calculation of the gravitational force between two objects
refers to the distance between their centers. 
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Moon's radius . . . . .  1,738 km  =  1.738 x 10⁶ meters
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<span>
and now we're ready to go !

       Gravitational force = 

                   G  M₁ M₂ / R²

= (6.67 x 10⁻¹¹ N-m²/kg²)(</span><span>5.972 x 10²⁴ kg)(7.348 x 10²²  kg)/</span>(8.098 x 10⁶ m)²

= (6.67 · 5.972 · 7.348 / 8.098²) · (10²³)      Newtons

=    (I get ...)        4.463 x 10²³ Newtons

That's almost exactly   10²³ pounds 

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7 0
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Always been observed to be true, law or theory?
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