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lora16 [44]
3 years ago
9

A seventh grade class is studying the solar system. A small group of students wanted to expand their studies to include the form

ation of black holes. The classroom teacher meets with this group on a daily basis to discuss their progress and offer additional help. This is an example of Tier ________ in the RtI model. a. I b. III c. All tiers d. IV
Physics
2 answers:
rodikova [14]3 years ago
7 0

Answer:by. III

Explanation:

Marizza181 [45]3 years ago
6 0

Answer:

The correct answer is letter "B": III.

Explanation:

The Response-to-Intervention (RTI) model is an educational approach provided to low-grade students by which teachers attempt to find out what children might be struggling with and based on the issues found teachers take different actions that could help students and their different forms of learning.

The RTI model is divided into three (3) tiers: <em>Tier I (The Whole Class), Tier II (Small Group Interventions), Tier III (Intensive Interventions).</em>

<em />

In Tier III, children require intensive intervention because they have gone through the previous two tiers with no results. Intensive intervention requires everyday sessions tailored for students and continuous evaluation to determine if additional help could be necessary.

Thus,<em> the small group of the class that is receiving specialized classes on Solar System everyday, represents educational help at the tier III in the RTI model.</em>

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Pani-rosa [81]

Answer:

intensity = 12.98 W/m^2

Energy = 3.93 J

Explanation:

As we know that the magnitude of electric field intensity is given as

E = 98.9 V/m

now we know that intensity of the wave is given as the product of energy density and speed of the wave

intensity = \frac{1}{2}\epsilon_0 E^2 c

intensity = \frac{1}{2}(8.85 \times 10^{-12})(98.9)^2(3\times 10^8)

intensity = 12.98 W/m^2

so intensity is the energy flow per unit area per unit of time

so the energy that flows through the area of 0.0259 m^2 in 11.7 s is given as

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Energy = 0.0259(11.7)(12.98)

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7 0
3 years ago
7. A toy car of mass 1.2 kg is driving vertical circles inside a hollow cylinder of radius 2.0m. It is moving at a constant spee
wlad13 [49]

Answer:

a)

N_{top}=9.8N\\N_{bottom}=33.4N

b) v_{min}=4.4m/s

Explanation:

The net force on the car must produce the centripetal acceleration necessary to make this circle, which is a_{cp}=\frac{v^2}{R}. At the top of the circle, the normal force and the weight point downwards (like the centripetal force should), while at the bottom the normal force points upwards (like the centripetal force should) and the weight downwards, so we have (taking the upwards direction as positive):

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Which means:

N_{top}=m\frac{v^2}{R}-mg=(1.2kg)\frac{(6m/s)^2}{2m}-(1.2kg)(9.8m/s^2)=9.8N\\N_{bottom}=m\frac{v^2}{R}+mg=(1.2kg)\frac{(6m/s)^2}{2m}+(1.2kg)(9.8m/s^2)=33.4N

The limit for falling off would be N_{top}=0, so the minimum speed would be:

0=m\frac{v_{min}^2}{R}-mg\\v_{min}=\sqrt{Rg}=\sqrt{(2m)(9.8m/s^2)}=4.4m/s

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