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DedPeter [7]
2 years ago
12

The diagram shows the molecular structure of propane. What is the chemical

Physics
2 answers:
ad-work [718]2 years ago
6 0

Answer:

B

Explanation:

Took the test

erica [24]2 years ago
4 0

Answer: B. C3H8

Explanation: Just took the test on A.PEX

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Silver has a mass of 10.5 grams and a volume of 19.3 cm3. What is its density?
Neko [114]

Answer:

<h3>The answer is 0.54 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question we have

density =  \frac{10.5}{19.3}  \\  = 0.54404145...

We have the final answer as

<h3>0.54 g/cm³</h3>

Hope this helps you

7 0
3 years ago
I need this right ASAP!!! plz plz plz
UkoKoshka [18]

Answer:

The answer is D

Nucleus is neutral

8 0
3 years ago
Read 2 more answers
A toy rocket, launched from the ground, rises vertically with an acceleration of 28 m/s 2 for 9.7 s until its motor stops. Disre
vredina [299]

Answer:

5080.86m

Explanation:

We will divide the problem in parts 1 and 2, and write the equation of accelerated motion with those numbers, taking the upwards direction as positive. For the first part, we have:

y_1=y_{01}+v_{01}t+\frac{a_1t^2}{2}

v_1=v_{01}+a_1t

We must consider that it's launched from the ground (y_{01}=0m) and from rest (v_{01}=0m/s), with an upwards acceleration a_{1}=28m/s^2 that lasts a time t=9.7s.

We calculate then the height achieved in part 1:

y_1=(0m)+(0m/s)t+\frac{(28m/s^2)(9.7s)^2}{2}=1317.26m

And the velocity achieved in part 1:

v_1=(0m/s)+(28m/s^2)(9.7s)=271.6m/s

We do the same for part 2, but now we must consider that the initial height is the one achieved in part 1 (y_{02}=1317.26m) and its initial velocity is the one achieved in part 1 (v_{02}=271.6m/s), now in free fall, which means with a downwards acceleration a_{2}=-9,8m/s^2. For the data we have it's faster to use the formula v_f^2=v_0^2+2ad, where d will be the displacement, or difference between maximum height and starting height of part 2, and the final velocity at maximum height we know must be 0m/s, so we have:

v_{02}^2+2a_2(y_2-y_{02})=v_2^2=0m/s

Then, to get y_2, we do:

2a_2(y_2-y_{02})=-v_{02}^2

y_2-y_{02}=-\frac{v_{02}^2}{2a_2}

y_2=y_{02}-\frac{v_{02}^2}{2a_2}

And we substitute the values:

y_2=y_{02}-\frac{v_{02}^2}{2a_2}=(1317.26m)-\frac{(271.6m/s)^2}{2(-9.8m/s^2)}=5080.86m

3 0
3 years ago
What is an equilibrant?
Stolb23 [73]
I’m pretty sure it is an object with a net force of zero. All forces are balanced and EQUAL
4 0
3 years ago
Which of the following must be true for “P if and only if Q” to be true?
erastovalidia [21]
Explain or message me what your trying to ask!

6 0
3 years ago
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