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Juliette [100K]

3 years ago

14

Which of the following are valid names for the triangle below? Check all that apply.

1 answer:

zhuklara [117]3 years ago

8 0

I would say:
B. KMD
C. DKM
and
E. MDK.

In reference it points to the edges which is how a triangle is usually depicted as.

I hope that helps clarify it, have a great rest of your day! ^ ^
{-Ghostgate-}

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Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

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A marker is 0.13 what is the length in millimeters

Flura [38]

If the marker is 0.13cm, then it is 13 millimeters.

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3 years ago

Four times one number minus three times another number is 12. Two times the first number added to three times to the second numb

SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

x = first number, y = second number

4x - 3y = 12

2x + 3y = 6

------------------add

6x = 18

x = 18/6

x = 3

4x - 3y = 12

4(3) - 3y = 12

12 - 3y = 12

-3y = 12 - 12

-3y = 0

y = 0

solution : (3,0)

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